The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
Answer:
One Solution
Step-by-step explanation:
x + 3y = 3
x - y = -3
4y = 6 Subtract to solve by elimination.
y = 
Divide by 4.
x - = -3 Substitute for y in the original equation.
x = - Add .
Answer:D the last one
Step-by-step explanation:
24000 + 3000x = 30000 + 2400x
3000x - 2400x = 30,000 - 24,000
600x = 6000
x = 6000/600
x = 10 years
Since y is anything greater than 2, you would draw a straight line across the point (from left to right) and if you had to shade you would shade above it (:
