Answer:
0.504 M
Explanation:
Step 1: Write the balanced neutralization reaction
2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O
Step 2: Calculate the reacting moles of KOH
55.2 mL (0.0552 L) of 0.500 M KOH react. The reacting moles of KOH are:
0.0552 L × 0.500 mol/L = 0.0276 mol
Step 3: Calculate the moles of H₂SO₄ that reacted with 0.0276 moles of KOH
The molar ratio of KOH to H₂SO₄ is 2:1. The reacting moles of H₂SO₄ are 1/2 × 0.0276 mol = 0.0138 mol
Step 4: Calculate the concentration of H₂SO₄
0.0138 moles of H₂SO₄ are in 27.4 mL (0.0274 L). The molarity of H₂SO₄ is:
[H₂SO₄] = 0.0138 mol/0.0274 L = 0.504 M
Answer is: solution B is saturated and solution A is unsaturated.
Saturated solution contains the maximum concentration of a solute dissolved in the solvent (usually water) and if extra solute is added to saturated solution, that solute will not dissolve.
Unsaturated solution means that more of a substance can be dissolved (in this example salt).
Each principal energy level above the first contains one s orbital and three p orbitals. A set of three p orbitals, called the p sub level, can hold a maximum of six electrons. Therefore, the second level can contain a maximum of eight electrons<span> - that is, two in the s orbital and 6 in the three p orbitals.
Hope this helps!! (If not sorry!)</span>
Sodium atom , potassium atom and cesium atom have the same group number which is group 1