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2 years ago

20 points!

Chemistry

2 answers:

Paladinen [302]2 years ago

8 0

Answer:

c and d

Explanation:

mitochondria and vacoule

Amanda [17]2 years ago

8 0

Answer:

It is actually D and A

Explanation:

I took this assignment before on edge and the guy who said C and D is wrong

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Determine the molarity of a solution prepared by dissolving 141.6 g of citric acid , c3h5o(cooh)3 , in water and then diluting t

gogolik [260]

The molarity of a solution prepared by dissolving 141.6g of citric acid in water is calculated as below

find the the number of moles

moles= mass/molar mass

= 141.6 g/ 192 g/mol = 0.738 moles

molarity= moles/molar mass

= 0.738/3500 x1000 = 0.21 M

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3 years ago

Entropy is greater at higher trophic levels than at lower levels.. True of False

loris [4]

Answer: True

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3 years ago

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Which is not a name to describe global winds A) Polar Easterlies B) Prevailing Westerlies C) Trade Winds D) Tropical Northerlies

SVEN [57.7K]

D Tropical northerlies

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3 years ago

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What happens if metal is in acid?<br> I'm having a blank

igomit [66]

Answer:

it dissolves or disintegrates

Explanation:

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2 years ago

How many grams of nitric acid HNO₃, are required to neutralize (completely react with) 4.30 grams of Ca(OH)2 according to the ac

Brrunno [24]

Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

• using the molar mass of Ca(OH)2 (74g/mol).

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

• using the molar mass of HNO3 (63.02g/mol).

$4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3$

So, 7.32g of HNO3 are required.

4 0

1 year ago