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Tom [10]
3 years ago
10

How many grams of hydrogen reacts with 32 g of oxygen to produce 34 g of hydrogen peroxide

Chemistry
1 answer:
nordsb [41]3 years ago
8 0

Answer:

2 grams.

Explanation:

H2 + O2 --->  H2O2

Using molar masses:

2*1 g hydrogen   reacts with 2*16  g oxygen.

so 2g H2 reacts with 32 g O2.

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If all of the energy from burning 281.0 g of propane (ΔHcomb,C3H8 = –2220 kJ/mol) is used to heat water, how many liters of wate
lapo4ka [179]

This problem is providing us with the mass of propane, its enthalpy of combustion, and the initial and final temperature of water that can be heated from the burning of this fuel. At the end, the result turns out to be 42.27 L.

<h3>Combustion:</h3>

In chemistry, combustion reactions are based on the burning of fuels by using oxygen and producing both carbon dioxide and water. For propane, we will have:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

Hence, we can calculate the heat released from this reaction by using the mass, which has to be converted to moles, and the given enthalpy of combustion:

Q=281.0g*\frac{1mol}{44.09g}*-2220\frac{kJ}{mol}*\frac{1000J}{1kJ}\\ \\ Q=-1.415x10^7 J

<h3>Calorimetry:</h3>

In chemistry, we can analyze the mass-specific heat-temperature-heat relationship via the most general heat equation:

Q=mC\Delta T

Thus, since Q was obtained from the previous problem, but the sign change because the released heat is now absorbed by the water, one can calculate the mass of water that rises from 20.0°C to 100.0°C with this heat:

m=\frac{Q}{C\Delta T} =\frac{1.415x10^7J}{4.184\frac{J}{g\°C}(100.0\°C-20.0\°C)}\\ \\m=4.227x10^4g

Finally, we convert it to liters as required:

V=4.227 x10^4g*\frac{1mL}{1.00g}*\frac{1L}{1000mL}  \\\\V=42.27L

Learn more about calorimetry: brainly.com/question/1407669

4 0
2 years ago
8. An elevator is moving upward with a speed of 11 m/s. Three
gizmo_the_mogwai [7]

Answer:

Average acceleration = - 2 m/s^2

Explanation: Have a nice day

3 0
3 years ago
Why is it not possible to always have a controlled experiment
lesantik [10]
A controlled experiment is one in which evrerything is held constant except for one verieble, maybe is usually a st of data is taken for a control group.
4 0
3 years ago
Calculate the enthalpy change, ΔH, for the process in which 30.1 g of water is converted from liquid at 10.1 ∘C to vapor at 25.0
gayaneshka [121]
You can split the process in two parts:

1) heating the liquid water from 10.1 °C to 25.0 °C , and

2) vaporization of liquid water at constant temperature of 25.0 °C.


For the first part, you use the formula ΔH = m*Cs*ΔT

ΔH = 30.1g * 4.18 j/(g°C)*(25.0°C - 10.1°C) = 1,874 J

For the second part, you use the formula ΔH = n*ΔHvap

Where n is the number of moles, which is calculated using the mass and the molar mass of the water:

n = mass / [molar mass] = 30.1 g / 18.0 g/mol = 1.67 mol

=> ΔH = 1.67 mol * 44,000 J / mol = 73,480 J

3) The enthalpy change of the process is the sum of both changes:

ΔH total =  1,874 J + 73,480 J = 75,354 J

Answer: 75,354 J
7 0
3 years ago
What element is 1s^2 2s^2 2p^6 3s2 3p^3
ruslelena [56]

Answer:

Phosphorus

Explanation:

If you add up all the electrons (the exponents) it equals 15 which is the atomic number of phosphorus. And since stable atoms have the same number of protons and electrons it'll be phosphorus

6 0
3 years ago
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