All categories

3 years ago

PLS HELP ME GUYSSSS...

Mathematics

1 answer:

gregori [183]3 years ago

6 0

Answer:

I believe it’s b could be wrong if I am I’m very sorry

Step-by-step explanation:

You might be interested in

during a state fair weekend the state gives away free admission 165 person that enters thefair on saturday 7925 people attend th

yKpoI14uk [10]

165 people get free admission

4 0

3 years ago

Read 2 more answers

Students were asked to explain the first step in solving the equation: 3y + 4 = 16. Susan says multiply by three. Ted says to ad

Juli2301 [7.4K]

Answer:

Nicole is correct

Step-by-step explanation:

They need to get the 3y on one side of the equal sign and the known numbers on the other side. To do this, they must subtract the 4 from both sides.

8 0

3 years ago

Increase 50 kg by 10%

PolarNik [594]

10% of 50kg is 5kg
50kg add 5kg is 55kg
=55kg

5 0

3 years ago

Read 2 more answers

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago

What is the compatible number of 3700 divided by 9

baherus [9]

The answer should be 411

5 0

3 years ago