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4 years ago

8

Whe might you read 0.203 as 2 tenths 3 thousandths

1 answer:

MAVERICK [17]4 years ago

6 0

Well, sometimes it is needed in word form. If someone asks you how much money you need in debt, you might say 1 tenth 4 hundredths. That is why you might need to read 0.203 as 2 tenths 3 thousandths.

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Hour how much does davon charge per hour for a skateboard rental HELPP I BEG

Setler79 [48]

Answer:

$7

Davon charges $7 per hour of rental

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3 years ago

What is the equation of a line with a slope of 2 and a y-intercept of -5?

skad [1K]

Answer:

y=2x-5

Step-by-step explanation:

The equation of a line is commonly written in slope-intercept form, or otherwise known as y=mx+b. Mx represents the slope and b represents the y-intercept.

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3 years ago

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Mike shoots a large marble (Marble A, mass: 0.05 kg) at a smaller marble (Marble B, mass: 0.03 kg) that is sitting still. Marble

Nadusha1986 [10]

<u>Answer</u>

1.333 m/s

<u>Explanation</u>

The momentum before collision and after collision is always conserved.

m₁v₁ = m₂v₂

(0.05×0.6) + (0.03×0) = (0.03 × v) + (0.05 × -0.2)

0.03 + 0 = 0.03v - 0.01

0.03v = 0.03+0.01

0.03v = 0.04

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= 4/3

=<em> 1.333 m/s</em>

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3 years ago

Find the volume of the cylinder

N76 [4]

Answer: wouldn't be 1608.5? let me know if im wrong.

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3 years ago

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V. Money Magazine reported that the average price of gasoline in the United States during the first quarter of 2008 was $3.46. A

Butoxors [25]

Answer:

$z=\frac{3.43 -3.46}{\frac{0.15}{\sqrt{30}}} = -1.095$

$z=\frac{3.49 -3.46}{\frac{0.15}{\sqrt{30}}} = 1.095$

And we can find this probability using the normal standard table and we got:

$P(-1.095$

Step-by-step explanation:

Let X the random variable that represent the price of a population, and for this case we know the distribution for X is given by:

$X \sim N(3.46,0.15)$

Where $\mu=3.46$ and $\sigma=0.15$

And for this case we want to find the following probability:

$P(3.43 \leq \bar X \leq 3.49)$

And we can use the z score formula given by:

$z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

If we find the z score for the limits we got:

$z=\frac{3.43 -3.46}{\frac{0.15}{\sqrt{30}}} = -1.095$

$z=\frac{3.49 -3.46}{\frac{0.15}{\sqrt{30}}} = 1.095$

And we can find this probability using the normal standard table and we got:

$P(-1.095$

8 0

4 years ago