Question

A regular octagon has a radius of 6 ft and a side length of

Answer 1

Answer:

Area of the regular octagon is approximately 102ft²

Step-by-step explanation:

Given the radius and length of a side of regular octagon as shown;

radius = 6ft and length of side = 4.6ft

Area of a regular octagon is expressed as $A = 2(1+\sqrt{2} )a^{2}$ where a is the length of one side. Given a = 4.6ft

Area = $A = 2(1+\sqrt{2} )(4.6)^{2}$

$= 2(1+\sqrt{2} )*21.16\\= (2+2\sqrt{2})*21.16\\ = 4.83*21.16\\= 102.20ft^{2}$

Area of the regular octagon is approximately 102ft²