A regular octagon has a radius of 6 ft and a side length of
1 answer:
Answer:
<h2>Area of the regular octagon is approximately 102ft²</h2>Step-by-step explanation:
Given the radius and length of a side of regular octagon as shown;
radius = 6ft and length of side = 4.6ft
Area of a regular octagon is expressed as where a is the length of one side. Given a = 4.6ft
Area =
Area of the regular octagon is approximately 102ft²
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Answer: The first option.
Step-by-step explanation:
1. The formula for calculate the perimeter is:
P=2l+2w
Where l is the lenght and w is the width.
2. The first perimeter is:
3. If you multiply the dimension by a scale of factor of 2, is the same as write the following expression:
Where is the first perimeter.
4. Then:
Answer:
solution given;
let
AB=a
AC=b=30ft
AB=c=20ft
<A=115°
By using Cosine rule.
a²=b²+c²-2bc cos angle
a²=30²+20²-2*30*20 Cos 115°
a²=1807.1419
a=√[1807.1419]
a=42.51
Side A is 42.51ft.
Again
Cos B=
Cos B=
Cos B=0.7687
<B=Cos -¹(0.7687)
<B=39.46°
Angle B is 39.46