Answer:
one of the quantities is a constant multiple of the other, or equivalently if they have a constant ratio
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
You first distribute within the parentheses which is -(-z-2). This is going to make everything positive as everything in the parentheses is negative. You should get z+2. Next, you plug that back in. It should be-3z+z+2. You simplify to get -2z+2. Hope this helps!
First, you should solve for
, which equals
. Now, solve the integral of
=
, to get that
. You can check this by taking the integral of what you got. Now by the Fundamental Theorem
![\int\limits^2_0 {4x} \, dx=[2x^2] ^{2}_{0}=2(2)^{2}-2(0)^2=8](https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E2_0%20%7B4x%7D%20%5C%2C%20dx%3D%5B2x%5E2%5D%20%5E%7B2%7D_%7B0%7D%3D2%282%29%5E%7B2%7D-2%280%29%5E2%3D8)
.
This should be the answer to your question, if I understood what you were asking correctly.
Answer:
Figure A is a translation of Figure 1
hope it helps...
Answer:
The regular price of the balls is $8
Step-by-step explanation:
The sporting goods store sales promotion is as follows;
The price of the third ball after buying two balls at regular price = $1.00
The price of the number of balls Coach John pays for the balls he bought = $136
To buy 24 balls, we have;
2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1
Therefore;
The number of balls bought at regular price = The sum of the 2s = 16 balls
The number of balls bought for $1 = 24 - 16 = 8 balls
Let x represent the regular price of the balls, we have;
16 × x + 8 = 136
16·x = 138 - 8 = 128
x = 128/16 = 8
The regular price of the balls = x = $8.
