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3 years ago

6

1 divided by root6 - root11 + root5. urgent

1 answer:

vodomira [7]3 years ago

3 0

1/√6 - √11 + √5

LCM = √6

(1 - (√6)*(√11) + (√5)*(√6) ) / √6

(1 - √(6*11) + √(5*6) )/ √6

Rationalize the surd by multiplying top and bottom by √6

((1 - √(6*11) + √(5*6) )/ √6) * (√6/√6)

(√6 - √(6*6*11) + √(5*6*6)) / √6

(√6 - 6√(11) + 6√(5)) / 6

So answer is:

(√6 - 6√11 + 6√5) / 6

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PLEASE HELP ME I HAVING TROUBLE

viktelen [127]

Answer: f(-6) = $-\frac{12}{11}$ , f(-4) = $\frac{8}{9}$ , f(4) = $-\frac{8}{9}$ , f(6) = $\frac{12}{11}$

<u>Step-by-step explanation:</u>

(-6, f(-6)) is an x,y coordinate. They are asking what the y-value is when you plug in -6 for x.

f(x) = $\frac{2x}{x^{2}-25}$

f(-6) = $\frac{2(-6)}{(-6)^{2}-25}$

= $\frac{-12}{36-25}$

= $-\frac{12}{11}$

f(-4) = $\frac{2(-4)}{(-4)^{2}-25}$

= $\frac{-8}{16-25}$

= $\frac{-8}{-9}$

= $\frac{8}{9}$

f(4) = $\frac{2(4)}{(4)^{2}-25}$

= $\frac{8}{16-25}$

= $\frac{8}{-9}$

= $-\frac{8}{9}$

f(6) = $\frac{2(6)}{(6)^{2}-25}$

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3 years ago

Can anyone help with this question pleasee

Vladimir [108]

Answer:

$y = 1$

Step-by-step explanation:

Given:

$a^{3y - 5} = \frac{1}{a^2}$

Apply the negative exponent rule

$a^{3y - 5} = a^{-2}$

The bases will cancel each other

$3y - 5 = -2$

$3y - 5 + 5 = -2 + 5$

$3y = 3$

$\frac{3y}{3} = \frac{3}{3}$

$y = 1$

7 0

3 years ago