Let its width be w and length= w+6
2(w+6+w)=52
4w+12=52
4w=40
w=10
Area=10*(10+6)=160
Answer:
6 vertices for triangular prisms.
Answer:
m∠M = 79°
m∠N = 66°
Step-by-step explanation:
∠MPN is supplementary to ∠MPQ, so m∠MPN = 35
The sum of the measures of a triangle is 180.
So, m∠M + m∠N + m∠MPN = 180
5y + 4 + 4y + 6 + 35 = 180
9y + 45 = 180
9y = 135
y = 15
m∠M = 5y + 4 = 5(15) + 4 = 75 + 4 = 79
m∠N = 4y + 6 = 4(15) + 6 = 66
Another way to do this problem, which is easier, is to know that an exterior angle of a triangle is equal to the sum of the two remote interior angles.
That means 5y + 4 + 4y + 6 = 145
9y + 10 = 145
9y = 135
y = 15
From knowing the value of y you can now find the measures of angles M and N
Lookin for free points kinda like this one whatcha doin?
Answer:
5 shirts must be sold.
Step-by-step explanation:
First, set up the equation. Each shirt (x) is sold for $16:
For every amount (y) for x: (y)(x) = (16)(y)
The cost is $4, with the setup fee as $60.
(16)(y) = (4)(y) + 60
16y = 4y + 60
Isolate the variable (y). Note the equal sign, what you do to one side, you do to the other. First, subtract 4y from both sides.
16y (-4y) = 4y (-4y) + 60
16y - 4y = 60
12y = 60
Next, isolate the variable (y). Divide 12 from both sides.
(12y)/12 = (60)/12
y = 60/12
y = 5
5 shirts must be sold.
To check, plug in 5 for y in the equation:
16y = 4y + 60
16(5) = 4(5) + 60
Simplify.
16(5) = 4(5) + 60
80 = 4(5) + 60
80 = 20 + 60
80 = 80 (True).
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