Answer:
Step-by-step explanation:
The letters are virtually impossible to read. I'll do my best, but recognize it is why you are not getting answers. I take y to be next to the 100 degree angle and part of the triangle.
I take x to be to the left of y. It is equal to the 28o angle because of the tranversal properties.
Finally z is the exterior angle of the triangle and as such has properties of z = y + 28 where y and 28 are remote interior angles to the triangle.
so x = 28 because of the transversal cutting the two parallel lines. They are equal by remote exterior angles of parallel lines.
y = 180 - 100 - 28 = 52
Finally z = 52 + 28 = 80 degrees because x and y add to 80 degrees.
If the assumptions are incorrect, could I trouble you to repost the diagram or correct the errors I have made.
Answer:
We need to sketch the problem first.
Find the size of angle R.
One member travels a distance of 12km due north. Another team member heads 50degree east of north and travels a distance of 10km.
If se substute 50° of 180 we have
180-50=130°
The distance between the two team members is the missing side.
We know two sides and included angle, so we use the cosine rule.
A2+b2+c2-2bcCosA
= 102+122-(2x10x12xcos130°)
=100+144-(-147.08)
=100+144+147.08
=391.08
A==SQRT391.08
=19.775
19.7km
Step-by-step explanation:
295×((((1+0.1÷4)^(4×6)−1)
÷(0.1÷4))×(1+0.1÷4))
=9,781.54
The length of the hypotenuse equals to the square root of the sum of the square of the other two sides.
12x12+16x16=144+256=400
The square root of 400 is 20.
By the same way, you can find the length of the hypotenuse of the reduced triangle
9x9+12x12=81+144=225
The square root of 225 is 15
The length of the hypotenuse is 15
The perimeter =12+9+15
The perimeter=36
