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kicyunya [14]
2 years ago
15

WILL MARK BRAINLIEST!!!!!

Mathematics
2 answers:
Mars2501 [29]2 years ago
8 0

Answer:

D

Step-by-step explanation:

Fudgin [204]2 years ago
6 0

Answer:

its D on edge

Step-by-step explanation:

i just took the test

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Y/7 - 4 = 5, solve for y, thanks!
barxatty [35]

The answer is Y = 63

Here's how I got my answer:

Step 1: Add 4 to both sides. Which leaves us with Y/7 = 5 + 4

Step 2: Simplify 5 + 4 to 9. Which leaves us with Y/7 = 9

Step 3: Multiply both sides by 7. Which leaves us with, your answer, Y = 63

6 0
3 years ago
Read 2 more answers
Peter is 2 years older than Winnie. Peter's age is 16 years less than seven times Winnie's age. The equations below model the re
GarryVolchara [31]
Given equations:
P=w+2
p=7w-16
Compare both equations
7w-16=w+2
Add 16 to both sides.
7w=w+18
Subtract w from both sides.
6w=18
Divide both sides by 6.
w=3, which is the age of Winnie.
Now Peter's age=3+2=5 years

Option A is the correct method to find the age of Peter and Winnie.

7 0
3 years ago
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Miranda has 4 lb 6 oz of clay is she divided it into 10 equal parts how heavy is each part?
natulia [17]
Each part would be 20z of Clay
8 0
3 years ago
What is a quotient ??? I do not understand
kirza4 [7]
A quotient is a answer or the sum
6 0
3 years ago
Read 2 more answers
A distributor of personal computers has five locations in a city. In the year's first quarter, the sales in units were: Location
Deffense [45]

Answer:

The correct option is (c) 13.277.

Step-by-step explanation:

The observed data is:

Location                      Observed sales (units)

Northside                                70

Pleasant Township                 75

Southwick                               70

I-90                                          50

Venice Avenue                       35

TOTAL                                   300

The test statistic for the Goodness of fit test is:

\chi^{2}=\sum\frac{(Observed-Expected)^{2}}{Expected}

For <em>k</em> independent samples this test statistic follows a Chi-square distribution with degrees of freedom (<em>k</em> - 1).

The sample size in this case is, <em>k</em> = 5.

The degrees of freedom is, (<em>k</em> - 1) = 4.

The level of significance is, <em>α</em> = 0.01.

The critical value of the test is:

\chi^{2}_{\alpha ,k-1}=\chi^{2}_{0.01,4}=13.277

**Use the Chi-square table.

Thus, the critical value is 13.277.

7 0
3 years ago
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