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3 years ago

What is expanded form 12.38

Mathematics

2 answers:

Aleks [24]3 years ago

6 0

Expanded form = Twelve and thirty- eight hundredths.<span>
</span>

Kruka [31]3 years ago

5 0

Twelve and thirty- eight hundredths.

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The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

Jaun's age, x, is 4 times his age 15 years ago

KIM [24]

The expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

<h3>How to rewrite the statement as an expression?</h3>

The mathematical statement is given as

Jaun's age, x, is 4 times his age 15 years ago

From the statement, we have:

x represent Juan's current age

This means that his age 15 years ago is

15 years ago = x - 15

4 times his age 15 years ago is

4 * 15 years ago = 4 * (x - 15)

The above equation is equivalent to his current age

So, we have

x = 4 * (x - 15)

Hence, the expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

Read more about expressions at

brainly.com/question/2972832

#SPJ1

7 0

1 year ago

Write the expression using exponents.<br><br>23 · y · y · y · y

Ostrovityanka [42]

Answer:

Exponent: 23y^4

3 0

2 years ago

Ryann planned on swimming 14 miles. Instead, he was only able to swim 1/4 of that distance. How many miles did Ryan swim?

mote1985 [20]

Hey there,

Given the question it shows that Ryann swam 1/4 of 14 miles that he was supposed to swim.

In words of is another way to say 1/4 * 14...

14/4

This expressed as a mixed number would be...

3 and 2/4 or 3 1/2

Of the 14 miles that Ryann was supposed to swim he swam 3 1/2 miles.

Hope I helped,

Amna

8 0

3 years ago

Read 2 more answers

The box plot represents the amount of time 15 pet owners spend exercising their pets each day.

Blizzard [7]

Right around 75 I would believe

4 0

3 years ago