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kirill [66]
3 years ago
8

4t+ 3.5 = 2.25 solve the equation ​

Mathematics
2 answers:
Fantom [35]3 years ago
7 0

Answer:

-0.3125

Step-by-step explanation:

Subtract 3.5 from both sides

4t = -1.25

Divide both sides by 4

t =. -0.3125

dangina [55]3 years ago
3 0

Answer:

1.3335

Step-by-step explanation:

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Y−3=2(x+1) solve this
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Answer:

Y-3 = 2(x+1)

open the brackets

Y-3 = 2x+2

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if were solving for x:

Y-3 = 2x+5

Y-8 = 2x

\frac{y}{2} -4 = x

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1 kilometre is how much miles​
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It failed to bring about peace and only angered King George III

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Let f(x)=x²-x-30<br><br> what are the zeros of the function?
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3 years ago
Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the
igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:  

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

Difference = 0,75

Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10

Mean of difference = 7.5/10

Mean of difference = 0.75

Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

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