Question

Given P(-7,3,-7) and Q(-4,-3,-9), find the midpoint of the segment PQ

Answer 1

Answer:

$P_x= -7, P_y = 3, P_z= -7$

$Q_x= -4, P_y = -3, P_z= -9$

Replacing we got:

$x= \frac{-7 -4}{2}= -\frac{11}{2}$

$y = \frac{3-3}{2}=0$

$z =\frac{-7-9}{2}= -8$

And then the midpoint would be:

$M= (-\frac{11}{2}, 0,-8)$

Step-by-step explanation:

We have the following two points P(-7,3,-7) and Q(-4,-3,-9) and the midpoint for this case is given by this:

$x= \frac{P_x +Q_x}{2}$

$y= \frac{P_y +Q_y}{2}$

$z= \frac{P_z +Q_z}{2}$

And from the problem given we have:

$P_x= -7, P_y = 3, P_z= -7$

$Q_x= -4, P_y = -3, P_z= -9$

Replacing we got:

$x= \frac{-7 -4}{2}= -\frac{11}{2}$

$y = \frac{3-3}{2}=0$

$z =\frac{-7-9}{2}= -8$

And then the midpoint would be:

$M= (-\frac{11}{2}, 0,-8)$

Answer 2

Answer:

The coordinates of the midpoint of the segment are (-5.5,0,-8)

Step-by-step explanation:

In this question, we are tasked with calculating the midpoint of the segment PQ.

To calculate this, we employ the use of a mathematical formula as follows;

The coordinate of the midpoint are = {(x1+x2)/2, (y1+y2)/2 , (z1+ z2)/2}

Thus we have;

{(-7-4)/2, (3-3)/2 , (-7-9)/2} = (-11/2, 0/2, -16/2)

= (-5.5,0,-8)