Answer:
see graph
Step-by-step explanation:
g(x) = 3^ x .
h(x) = 2^-x
We want to subtract them
f(x) = 3^x - 2^(-x)
I will rewrite without the negative exponent
f(x) = 3^x - (1/2)^(x)
Lets pick a couple of points
f(0) = 3^0 - (1/2) ^ 0 = 1-1 = 0
As x gets large 3^x gets large and 1/2^x gets close to 0, so it will get large
As x goes to negative infinity, 3^x goes to zero and 1/2^ gets large so we get - infinitity
Remark
That was well worth doing. Desmos gave you the answer to the graph. Unfortunately I can only give you the correct graph. You will have to figure out from the choices which one is the correct answer -- or edit it so I can see what the rest of the question is.
Graph
The red one is f(x) is x + 3 {x <= -2}
The blue one is f(x) is x^2 - 1 {-2 <x <1} Notice the gap at 2. It is not continuous
The green one is f(x) is log_2(-x + 3) {1 <=x < 3} and there is a gap between the blue and green one.
