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Paraphin [41]
3 years ago
10

If two opposite sides of a square are increased by 8 meters and the other sides are decreased by 5 meters, the area of the recta

ngle that is formed is 68 square meters. Find the area of the original square.
Mathematics
1 answer:
Alchen [17]3 years ago
5 0

Answer:

21

Step-by-step explanation:

8 * 2 = 16

5 * 2 = 10

68 - 16 = 52 - 10 = 42.

The perimeter of the square is 42.

42 / 4 = 10.5. 10.5 is the length of a side.

10.5 * 2 = 21.

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What is the z-score that corresponds to a cumulative area of 0.0122?
LUCKY_DIMON [66]
The z-score corresponding to a cumulative area of 1 - 0.0122 = 0.9878 is 2.25.
Therefore the z-score corresponding to a cumulative area of 0.0122 is the negative of 2.25 = -2.25.
5 0
3 years ago
You go outside and step on a frog, the sand is yellow because the grass was 42, therefore the rabbit hopped 39 degrees upwards.
Zina [86]

Answer:

40

Step-by-step explanation:

its 40 because bob is orange.

8 0
2 years ago
Read 2 more answers
Suppose that demand in period 1 was 7 units and the demand in period 2 was 9 units. Assume that the forecast for period 1 was fo
Zepler [3.9K]

Answer:

Step-by-step explanation:

Forecast for period 1 is 5

Demand For Period 1 is 7

Demand for Period  2 is 9  

Forecast  can be given by

F_{t+1}=F_t+\alpha (D_t-F_t)

where

F_{t+1}=Future Forecast

F_t=Present\ Period\ Forecast

D_t=Present\ Period\ Demand

\alpha =smoothing\ constant  

F_{t+1}=5+0.2(7-5)

F_{t+1}=5.4

Forecast for Period 3

F_{t+2}=F_{t+1}+\alpha (D_{t+1}-F_{t+1})

F_{t+2}=5.4+0.2\cdot (9-5.4)

F_{t+2}=6.12  

8 0
3 years ago
(a) The parametric equations x = f(t) and y = g(t) give the coordinates of a point (x, y) = (f(t), g(t)) for appropriate values
Gnesinka [82]

Answer:

Step-by-step explanation:

a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.

b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).

c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following

y=t^2 = (x)^2 = x^2

where x\geq 0

5 0
3 years ago
A 1L IV contains 60meq of kcal. The IV was discontinued after 400ml has infused. How much lvl did the patient receive
Leya [2.2K]

If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.

Calculation for the Amount of IV

It is given that,

1L IV contains 60meq of kcal

⇒ 1000 mL of IV contains 60meq of kcal

⇒ 1 mL of IV will contain 60 / 1000 meq of kcal

As per the question,

The amount of IV infused in the patient = 400 mL

⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)

= 4 × 6

= 24 meq of kcal

Hence, the patient receives 24meq of kcal amount of IV.

Learn more about amount here:

brainly.com/question/4567186

#SPJ1

6 0
2 years ago
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