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Anvisha [2.4K]
3 years ago
5

The curve y = ax^2 + bx + c passes through the point (2, 32) and is tangent to the line y = 4x at the origin. Find the values of

a, b, and c.
Mathematics
1 answer:
Arada [10]3 years ago
8 0
We are given the general formula of the curve of y = ax2 + bx + c. The tangen line at the origin is y = 4x. This eliminates the second term in which the derivative should be reflected as a constant. Since when the derivative of the first term is 4x, then a should be 2. From the points, c should be equal to 24.
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A line that has a rise of -34 and a run of 20.
aleksandr82 [10.1K]

Answer:

y=-1.7x-34

Step-by-step explanation:

An equation of a line is given y=mx+c, where m is the gradient or \frac{Rise}{Run}

The rise indicates the change in value of y (vertical change in the graph).

The run indicates the change in value of x (horizontal change in the graph).

Let point 1 of the graph be (x,y) = (0,-34) and point 2 be (x,y) = (20,0).

 m =\frac{Rise}{Run} \\  =\frac{-34}{20}\\  =-1.7

Substitute point 1 into the graph to get the constant c.

y=mx+c

-34=(-1.7)*(0)+c

c=-34

∴ The equation of the line is, y=-1.7x-34

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Step-by-step explanation:

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The logarithmic function is the inverse of the exponential function. Thus, we can write

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3 years ago
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