Older and did not have that type of match that is on applications.
At the end of three days,
% of the original amount of liquid remains in Kyle's container .
<u>Step-by-step explanation:</u>
Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:
Let's suppose initially we have 100% of liquid present so ,
<u>At day 1:</u>
10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
<u>At day 2:</u>
10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
<u>At day 3:</u>
10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
Therefore , At the end of three days,
% of the original amount of liquid remains in Kyle's container .
This question doesn’t really make sense- is it multiple choice, if so what are the options? A can be anything as long as it’s the same?
2x^2 + 16x + 34 = 0
x^2 + 8x + 17 = 0
x^2 + 8x + 16 = -17 + 16 = -1
(x + 4)^2 = -1
x + 4 = sqrt(-1) = ±i
x = -4 <span>±</span> i