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seropon [69]
2 years ago
8

Someone pls help me with this

Mathematics
1 answer:
Vesna [10]2 years ago
5 0

Answer:

1 =125

2=55

3=95

...........

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1/2,1/3,1/8 find the sum
Zarrin [17]

Answer:

23/24

Step-by-step explanation:

To find the sum you must ad.

Fractions can only be added and subtracted when the denominators (the bottom numbers) are the same.

24 is the smallest number that 2, 3 and 8 go into.

1/2 = 12/24, 1/3 = 8/24, 1/8 = 3/24

\frac{12}{24} + \frac{8}{24} + \frac{3}{24} = \frac{23}{24}

23/24

4 0
4 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Find the value of x.<br> (x + 30)
taurus [48]

Answer:

x=55

Step-by-step explanation:

The exterior angles of a polygon add to 360.

x+x+x+x+x+x+30 = 360

Combine like terms

6x+30 = 360

Subtract 30 from each side

6x+30-30 = 360-30

6x = 330

Divide by 6

6x/6 =330/6

x =55

8 0
3 years ago
True or False: If lim x → a f(x) does not exist, then f is undefined at the point x = a.
kkurt [141]

Answer:

this is absolutely false.

8 0
3 years ago
Suppose 60% of kids like video games. Predict the number of kids that prefer video games out of a group of 200 kids.
myrzilka [38]

Answer:

120 kids prefer video games

Step-by-step explanation:

60% is .60

multiply .60 by 200 to get your answer.

.60 × 200 = 120

4 0
3 years ago
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