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3 years ago

Graph y−5=−23(x+9) using the point and slope given in the equation. Use the line tool and select two points on the line.

Mathematics

2 answers:

laiz [17]3 years ago

8 0

Answer here is correct hope this helps :)

jarptica [38.1K]3 years ago

7 0

Maybe try (-9, 6) and (-9,5)
i think it may be correct

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Answer:

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(2x-1)(x+4)=2x^2-x+8x-4=2x^2+7x-4

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The graph of y=x^3 is transformed as shown in the graph below. With. Equation represents the transformed function

taurus [48]

Answer: y' = (-x)^3 - 4

Step-by-step explanation:

The graph y = f(x) = x^3 passes trough the point (0,0)

because when x = 0

f(0) = y = 0^3 = 0

in the graph of the image, we can see that the graph intersects the y-axis in the point (0, -4)

This means that we have a vertical displacement of 4 units downwards.

When we have a graph y = f(x), a vertical translation of A units can be written as

y' = f(x) + A

If A is positive, the displacement is upwards, if A is negative, the displacement is downwards.

So if the displacement is of 4 units down, A = -4

We also have that when x is negative, the value of y is positive.

But in our original function, we have that for x = -1, y = (-1)^3 = -1

so in our original function, when x is negative also does y.

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3 years ago

If a 4 x 16 rectangle has the same area as a square, what is the length of a side of the square?

Licemer1 [7]

Answer:

Option D. 8 units

Step-by-step explanation:

step 1

Find the area of rectangle

The area of rectangle is

$A=(4)(16)=64\ units^2$

step 2

Find the length side of the square with the same area of rectangle

The area of a square is

$A=b^2$

where

b is the length side of the square

we have

$A=64\ units^2$

substitute

$64=b^2$

take the square root both sides

$b=8\ units$

therefore

The length side of the square is 8 units

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3 years ago

Graph ​ y−5=−23(x+9) ​ using the point and slope given in the equation. Use the line tool and select two points on the line.

Graph y−5=−23(x+9) using the point and slope given in the equation. Use the line tool and select two points on the line.