Given that,
Mass of student 1, m₁ = 90 kg
Mass of student 2, m₂ = 60 kg
Speed of student 1, v₁ = 5 m/s
To find,
The velocity of the other student.
Solution,
Using the conservation of momentum to find the velocity of the other student. Let it is v₂.
So, the velocity of the other student is 7.5 m/s.
Answer:
3.33 ohms
Explanation:
Parallel circuit :
1/Rtotal= 1/R1 + 1/R2 + 1/R3
1/Rtotal= 1/10 + 1/10 + 1/10
1/Rtotal=3/10
Therefore it Rtotal= 10/3=3.33 ohms
Answer:
by obtaining the total mass of the dimes present:
d = 27.22 g / dozen the density of dimes
M = n * d = 5 dozen * 27.22 g / dozen = 126.1 g
There are several differences between<span> a </span>physical and chemical change<span> in matter or substances. A </span>physical change<span> in a substance doesn't </span>change<span> what the substance is. In a </span>chemical change<span> where there is a </span>chemical<span> reaction, a new substance is formed and energy is either given off or absorbed.</span>
Orbital periods of stars in the Galaxy