Answer:
1mole of Argon contains 6.022x10^23atoms
3moles will contain
3x6.022x10^23atoms
1 atoms of Argon contains 18electrons
3x6.022x10^23atoms will contain...
3x6.022x10^23 x 18electrons
= 3.252x10^25electrons
Note:In a Neutral Argon... No of Electrons and Protons(positive charge) are the same
From Charge Quantization Principle
Q=ne
n=3.252x10^25protons
e=1.6x10^-19C
Q=3.252x10^25 x 1.6x10^-19
Q=5.2x10^6C
what type of question is that man ?
Answer:
<em>The rebound speed of the mass 2m is v/2</em>
Explanation:
I will designate the two masses as body A and body B.
mass of body A = m
mass of body B = 2m
velocity of body A = v
velocity of body B = -v since they both move in opposite direction
final speed of mass A = 2v
final speed of body B = ?
The equation of conservation of momentum for this system is
mv - 2mv = -2mv + x
where x is the final momentum of the mass B
x = mv - 2mv + 2mv
x = mv
to get the speed, we divide the momentum by the mass of mass B
x/2m = v = mv/2m
speed of mass B = <em>v/2</em>
Answer:
6.3 C
Explanation:
From the question,
Energy lost by the capacitor(half it stored energy) = 1/4CV².......................... Equation 1
Where C = Capacitance of the capacitor, V = Volatge across the parallel plate of the capacitor.
E = 1/4CV²
Given: C = 2.1 F, V = 6.0 V
Substitute these values into equation 1
E = 1/4(2.1)(6²)
E = 18.9 J
But,
E = 1/2QV..................... Equation 2
Where Q = amount of charge lost
Make Q the subject of the equation
Q = 2E/V................. Equation 3
Give: E = 18.9 J, V = 6.0 V
Q = 2(18.9)/6
Q = 6.3 C.
Answer:
5.63 atm
Explanation:
P1 = 5 atm
P2 = ?
T1 = 5 °C = 5 + 273 = 278 K
T2 = 40 °C = 273 + 40 = 313 K
Let the pressure is P2.
Use
Pressure is directly proportional to the absolute temperature as the volume remains constant.
P2 = 5.63 atm
Thus, the pressure is 5.63 atm.