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denis-greek [22]
3 years ago
9

Serena is a research student who has conducted an experiment on the discoloration of marble. Read about Serena’s experiment. The

n identify two flaws in her experiment’s design.
Serena sees an article about the Taj Mahal, a medieval marble monument in India. She reads that the white monument is beginning to turn a dull yellow-brown. Serena admires the Taj Mahal and is eager to learn what might be causing the yellowing. She formulates a hypothesis that the yellow-brown tinge may be caused by air pollution from black carbon, brown carbon, or methane, combined with wind erosion.

To test her hypothesis, she decides to study the effects of these air pollutants and wind on white marble. She finds three identical pieces of white marble and exposes one of them to air containing black carbon, one to air with brown carbon, and one to air with methane. She also places a fan on two of the samples, varying the speed of the air stream in regular intervals. After a few days, the marble samples begin changing color, becoming grayish. Serena learns that air pollution caused the discoloration. However, she is not sure how it became gray instead of yellow and what exactly caused the discoloration.

She used identical pieces of marble for her samples.
She introduced at least one confounding variable.
She tried to test multiple hypotheses at a time.
She attributed the marble discoloration to wind erosion.
She used a mechanically-generated air stream rather than natural 
Physics
1 answer:
sergij07 [2.7K]3 years ago
3 0

The two flaws in her experiment’s design are

<span>- She introduced at least one confounding variable.</span> <span>- She tried to test multiple hypotheses at a time</span>

 In the above mentioned experiment she had to have four samples to prove four hypotheses, each one separately and not to mix two hypotheses in an alone sample, that what it brings as consequence is the confusion.

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3 years ago
A physics professor did daredevil stunts in his spare time. His last stunt was an attempt to jump across a river on a motorcycle
tatiyna

Answer:

a) 17.8 m/s

b) 28.3 m

Explanation:

Given:

angle A = 53.0°

sinA = 0.8

cosA = 0.6

width of the river,d = 40.0 m,

the far bank was 15.0 m lower than the top of the ramp h = 15.0 m,

The river itself was 100 m below the ramp H = 100 m,

(a) find speed v

vertical displacement

-h= vsinA\times t-gt^2/2

putting values h=15 m, v=0.8

-15 = 0.8vt - 4.9t^2  ............. (1)

horizontal displacement d = vcosA×t = 0.6×v ×t

so v×t = d/0.6 = 40/0.6

plug it into (1) and get

-15 = 0.8\times40/0.6 - 4.9t^2

solving for t we get

t = 3.734 s

also, v = (40/0.6)/t = 40/(0.6×3.734) =  17.8 m/s

(b) If his speed was only half the value found in (a), where did he land?

v = 17.8/2 = 8.9 m/s

vertical displacement = -H =v sinA t - gt^2/2

⇒ 4.9t^2 - 8.9\times0.8t - 100 = 0

t = 5.30 s

then

d =v×cosA×t = 8.9×0.6×5.30= 28.3 m

3 0
3 years ago
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