Answer:
Explanation:
A )
The ball floats with half of it exposed above the water level . So it must have density half that of water . In other words its density must have been 500 kg / m³
B )
Tension in the ball will be equal to net force acting on the ball
Net force on the ball = buoyant force - weight .
4/3 x π x .21³ x 10⁻⁶ x 9.8 ( 1000 - 893 )
= 40.65 x 10⁻⁶ N .
C )Tension in the 3 rd ball will be equal to net force acting on the ball
Net force on the ball = weight - buoyant force
= 4/3 x π x .21³ x 10⁻⁶ x 9.8 ( 1320 - 1000 )
= 121.6 x 10⁻⁶ N .
Vi = 0 m/s
Vf = 27 m/s
t = 9 min = 540 s
1 min = 60 s
9 min = 540 s
a = ? m/s^2.
vf = vi + at
27 = 0 + 540a
27 = 540a
27/540 = 540a/540
27/540 = a
0.05 = a.
The truck's acceleration was 0.05 m/s^2.
<span>This would be an isotropic object. Having isotropy means that, in every direction that the object could be measured, a similar (or the same) value or measure would be reached. This allows an object to be easier to shape and makes it easier to understand and predict the object's behavior under different circumstances.</span>