Write an equivalent expression for 4g+2 using the distributive property.

WILL AWARD BRAINIEST: Find the area of the shaded polygons below:

IRINA_888 [86]

Answer:

<h2>9 square units</h2>

Step-by-step explanation:

You can use the Pick's formula:

$A=i+\dfrac{b}{2}-1$

Where

$i$ - the number of lattice points inside the polygon

$b$ - number of lattice points on the border located on the perimeter of the polygon

From the picture we have:

$i=5\\\\b=10$

Substitute:

$A=5+\dfrac{1}{2}\cdot10-1=5+5-1=10-1=9$

4 0

3 years ago

Expand<br> 8(10-c)<br> ........................................................

Lady_Fox [76]

Answer:

80 - 8c

Step-by-step explanation:

8(10-c)

80 - 8c

5 0

3 years ago

Read 2 more answers

Consider a triangle ABC like the one below. Suppose that a = 42, b=44, and c= 52. (The figure is not drawn to scale.) Solve the

maksim [4K]

In the triangle , Angle A is 51.1 degrees, B is 54.5 degrees , C is 74.4 degrees.

<h3>What is a Triangle ?</h3>

A triangle is defined as a polygon with three sides , three angles and three vertices.

Using the Law of Cosine to solve the Triangle and to determine the value of all the angles

c² = a²+ b² -2abCosC

a = 42 , b=44 , c = 52

52² = 42² + 44² -2 * 42 * 44 cos C

2704 = 1764 + 1936 -3696 cos C

cos C = 0.269

C =74.4 ° (degrees)

Similarly calculating for A and B will give

Angle A is 51.1 degrees

Angle B is 54.5 degrees

To know more about Triangle

brainly.com/question/2773823

#SPJ1

6 0

2 years ago

pqrs is a rectangle with sides ps=5cm and pq =12cm find the length of qr ,sr and the two diagonals pr and qs.

never [62]

<h3>Given:</h3>

PQRS is a rectangle.

PS = 5cm

PQ = 12cm

The length of qr ,sr and the two diagonals pr and qs.

<h3>Solution:</h3>

Opposite sides of a rectangle are equal.

QR = PS = 5cm

SR = PQ = 12cm

By using Pythagoras Theorem, we get

PR = √PS^2 + SR^2

or, PR = √25 + 144

or, PR = √169

or, PR = 13cm

Diagonals of a rectangle are equal.

QS = PR = 13cm

<h2>Answer:</h2>

QR = 5 cm

SR = 12 cm

PR = 13 cm

QS = 13 cm

7 0

4 years ago

Teen Court is a juvenile diversion program designed to circumvent the formal processing of first-time juvenile offenders within

valentinak56 [21]

Answer:

Z-statistic = 1.4017 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

The data suggest that the true proportion of Teen Court individuals who recidivate during the specified follow-up period differs from the proportion of Department of Juvenile Services individuals

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given first sample size (n₁ ) = 57

Of the 57 Teen Court individuals, 18 subsequently recidivated during the 18-month follow-up period

First sample proportion

$p^{-} _{1} = \frac{x_{1} }{n_{1} } = \frac{18}{57} =0.3157$

Second sample proportion

$p^{-} _{2} = \frac{x_{2} }{n_{2} } = \frac{11}{54} =0.2037$

Null Hypothesis : p₁⁻ = p₂⁻

Alternative Hypothesis : p₁⁻ ≠ p₂⁻

<u><em>Step(ii)</em></u>:-

Test statistic

$Z = \frac{p_{1} ^{-} -p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }$

where

$P = \frac{n_{1}p^{-} _{1} +n_{2} p^{-} _{2} }{n_{1} +n_{2} }$

$P = \frac{57 X0.3157+0.2037X54}{54+57} = 0.2612$

Q = 1 - P = 1 - 0.2612 = 0.7387

$Z = \frac{0.3157-0.2037}{\sqrt{0.2612 X0.7387 (\frac{1}{57} +\frac{1}{54} )} }$

Z = 1.4017

Level of significance ∝ =0.05

The tabulated value Z₀.₀₅ = 1.96

Z-statistic = 1.4017 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

The data suggest that the true proportion of Teen Court individuals who recidivate during the specified follow-up period differs from the proportion of Department of Juvenile Services individuals

7 0

3 years ago