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Tresset [83]
3 years ago
6

Carol rolled a dice 150 times. She rolled six 39 times. Use carols data to estimate the probability of rolling six with the dice

. Give answer in fraction
Mathematics
1 answer:
Makovka662 [10]3 years ago
4 0

Answer: 13/50

Step-by-step explanation:

The original fraction is 39/150

Simplify that gives 13/50 to get the probability of rolling six with the dice

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If 3x+y=6 what is the of 6x+2y
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Answer:

12

Step-by-step explanation:

3x + y = 6

Multiply both sides by 2

6x + 2y = 12

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Is this the whole question?
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Which of the h-values satisfy the following inequality 6 ( greater than or equal to sign ) h/2?
Amiraneli [1.4K]

Start from

6 \geq \dfrac{h}{2}

Multiply both sides by 2:

12 \geq h

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h \leq 12

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3 years ago
Fin the sum (3/8x-2)+(1/8x-5)
Elan Coil [88]

Answer:

1/2x-7

Step-by-step explanation:

Add 3/8x and 1/8x to get 4/8x which is the same as 1/2xThen add the integers: -2 + -5 = -7.

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8 0
1 year ago
In European roulette, the wheel is divided into 37 compartments numbered 1 through 36 and 0. (In American roulette there are 38
earnstyle [38]

Answer:

The expectation is -$0.189.

Step-by-step explanation:

Consider the provided information.

In European roulette, the wheel is divided into 37 compartments numbered 1 through 36 and 0.

One-half of the numbers 1 through 36 are red, the other half are black, and the number 0 is green.

We need to find the expected value of the winnings on a $7 bet placed on black in European roulette.

Here the half of 36 is 18.

That means 18 compartments are red and 18 are black.

The probability of getting black in European roulette is 18/37

The probability of not getting black in European roulette is 19/37. Because 18 are red and 1 is green.

If the ball lands on a black number, the player wins the amount of his bet.

The bet is ball will land on a black number.

The favorable outcomes are 18/37 and unfavorable are 19/37.

Let S be possible numerical outcomes of an experiment and P(S) be the probability.

The expectation can be calculated as:

E(x) = sum of S × P(S)

ForS_1 = 7

P(S_1) = \frac{18}{37}

For S_2 = -7(negative sign represents the loss)

P(S_2) = \frac{19}{37}

Now, use the above formula.

E(x) = 7\times \frac{18}{37}-7\times \frac{19}{37}\\E(x) = -0.189

Hence, the expectation is -$0.189.

4 0
3 years ago
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