Answer:
33.3% probability that both children are girls, if we know that the family has at least one daughter named Ann.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The family has two children.
The sample space, that is, the genders of the children may be divided in the following way, in which b means boy and g means girl.
b - b
b - g
g - b
g - g
We know that they have at least one girl. So the sample space is:
b - g
g - b
g - g
What is the probability that both children are girls, if we know that the family has at least one daughter named Ann?
Desired outcomes:
Both children being girls, so
g - g
1 desired outcome
Total outcomes
b - g
g - b
g - g
3 total outcomes
Probability
1/3 = 0.333
33.3% probability that both children are girls, if we know that the family has at least one daughter named Ann.
Sub the point into the inequality
2(4)-3<4
8-3<4
5<4
Therefore, no, it is not a solution because 5 is not less than 4
Hope this helps!
Answer:
81%
Step-by-step explanation:
divide 162 by 200
Answer:
68%
Step-by-step explanation:
The mean is 32 minutes, and the standard deviation is 4 minutes.
28 is 1 standard deviation below the mean, and 36 is 1 standard deviation above the mean.
According to the empirical rule, 68% of a normal distribution is between -1 and 1 standard deviations. 95% is between -2 and 2 standard deviations. 99.5% is between -3 and 3 standard deviations.
So the answer is 68%.
