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Crank
3 years ago
5

PLEASE HELP QUICK

Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0

y = 150(8 x 12)

y = 14,400

The store ordered a total of 14,400 ounces of soap.

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P l e a s e h e l p m me !!!
NemiM [27]

Answer:

C

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
What is the Simplified form of √46/192
Lorico [155]

Answer:

  (√138)/24

Step-by-step explanation:

\displaystyle\sqrt{\frac{46}{192}}=\sqrt{\frac{46\cdot 3}{192\cdot 3}}=\sqrt{\frac{138}{24^2}}=\frac{\sqrt{138}}{24}

8 0
3 years ago
Ignoring leap days, the days of the year can be numbered 1 to 365. Assume that birthdays are equally likely to fall on any day o
faust18 [17]

Answer:

Follows are the solution to the given question:

Step-by-step explanation:

They can count the days of the year 1 to 365. The random project consists of drawing a sample of n objects from D where elements are n people's birth in a group but instead, D = {1,....365}. And then there's the issue.

S=365^n

This because the list of future birthdays of n people was its test point; therefore m points will be in the sequence so each point contains 365 distinct outcomes. The probability function P for \Omega is that any event is likely to happen in 365 days.

P(x)=\frac{1}{365^{n}}

if x is between 1 and 365 as well as the occurrence is just all similarly possible

In point i:

That somebody mentions their birthday throughout the party

Guess I was born on day b. Therefore the consequence of "x is in A" is "b is now in the series of x," which is to say, b = bk for some amount k approximately 1 and n.

In point ii:

Any 2 persons share the same birthday at this party". A result x is in B" means which "two of entries in x are same." This means that perhaps the outcome x is in B if or only if bj = bk is in B of two numbers j, and k of 1, of two. , no, n.

In point iii:

Many three students share the same birthday with both the party. The consequence is x at the level of C only when bj = bk = bl at three (different) indices, j, k, l, 1. , no, n.

6 0
3 years ago
Find the thirteenth term of an arithmetic sequence if the first term is 3 and the common difference is 3
lesya692 [45]

Answer:

39

Step-by-step explanation:

Formula for the nth term (an) = a1 + d(n - 1)  where a1 = the first term and d = common difference.

So here the 13th term = 3 + 3(13 - 1)

= 3 + 3*12

= 39  (answer).

8 0
3 years ago
Please help me ASAP!
baherus [9]

Answer:

I think it is 15

Step-by-step explanation:

3 0
3 years ago
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