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Colt1911 [192]
3 years ago
13

Please help me fr im struggling

Mathematics
1 answer:
Alchen [17]3 years ago
4 0

Answer:

x = 3

m<PAW = 1

Step-by-step explanation:

☆They are supplementary angles.

☆Supplementary angles equal 180 degrees.

- 11x + 17 3 - 1x + 43 = 180 \\  - 12x + 216 = 180 \\  \frac{  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: - 216 =  - 216}{ \frac{ - 12x}{ - 12}  =  \frac{ - 36}{ - 12} }  \\ x = 3

☆Plug in for m<AEZ

- 1(3) + 4 \\  - 3 + 4  \\ 1

☆m<PAW is corresponding to m<AEZ

☆Corresponding angles are congruent.

☆m<PAW equals 1.

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If f (1)= -2, then the point is on the graph of f
Komok [63]
<h3>Answer:  (1, -2)</h3>

Explanation:

Writing f(1) = -2 means x = 1 and y = f(x) = -2 pair up together

So we have (x,y) = (1, -2) as the point on the f(x) curve.

6 0
3 years ago
PLS HELPPPP<br> Solve 3x2 + 18x + 15 = 0 by completing the square. <br> I CANT FIND REAL ANSWER!
Dmitriy789 [7]

Answer:

x = − 1 , − 5

7 0
3 years ago
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The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
Two angles in a triangle have measures of 23 and 98 what is the third measure of the third angle
Feliz [49]

Answer:

59

Step-by-step explanation:

As far as I know every triangle has to equal 180°

So if you add 98+23 you would get 121

subtract that from 180 and get 59

Hope this helps!

5 0
3 years ago
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inn [45]
5x + 3y = 460
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Use elimination subtraction
-2y = -140
y = 70
There are 70 student tickets
3 0
3 years ago
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