We are given total 10 tree seedlings.
Number of workshops = 2.
Here order doesn't matters.
<em>When order doesn't matters we apply combination.</em>
We know formula of combination:
For the given situation, we have
n=10 and r=2.
Plugging values in formula, we get
<h3>Therefore, 45 different ways can the nursery give out seedlings.</h3>
Only 2 forces are out of balance - the 22N and the 14N
So the resultant force is 22-14 = 8N.
(10(1-(1/2)^5)/1-(1/2) =
20(1-1/32)
=155/8
Give me the points thanks
Answer:
<em>(9,-5)</em>
Step-by-step explanation:
When you go down, the number will decrease. The vertical position is the Y axis. -3-2=5.
When you go right, the number will increase. The horizontal position is the X axis. 5+4=9
<em>(9,-5)</em>
<u>Hope this helps :-)</u>
