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3 years ago

How to solve 12ax-2ax+14x-2a+ -3x

1 answer:

8 0

That long, messy expression is not an equation and it's not a question,
so there's nothing to solve or answer. However, it IS long and messy, so
your homework assignment might be to 'simplify' it. Here's how:

12ax - 2ax + 14x - 2a + -3x

Everything we'll do to this is called "combine like terms". That means
"combine terms that are alike". Terms are alike when they have the
same letter variables.

12ax and -2ax are like terms. Combine them, and you get 10ax .

14x and -3x are like terms. Combine them, and you get 11x .

So now we have: 10ax + 11x + 2a .

Nothing has been changed. This shorter, simpler expression has
exactly the same value as the original long messy one has. It has
just been cleaned up, and it looks neater and simpler.

You might also be expected to 'factor' the expression. I don't know.
If you want to do that, then you could do it in 2 different ways . . .
either factor the 'x' from the two terms that have 'x' in them, or
else factor the 'a' from the two terms that have 'a' in them.
Without explanation, here's how those would look:

x(10a + 11) + 2a
or
a(10x + 2) + 11x .

Again, nothing has changed. Both of these have the same value, and
their value is the same as the value of the long messy expression in
the question.

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Mae has a number cube with 6 sides that are numbered 1 through 6. What is the probability that Mae will roll an odd number?

Stels [109]

Answer:

C) $P(E) = \frac{3}{6}$

The probability that Mae will roll an odd number

$P(E) = \frac{3}{6}$

Step-by-step explanation:

Step(i):-

Given that Mae has a number cube with 6 sides that are numbered 1 through 6.

n(S) = { 1,2,3,4,5,6,} = 6

Let 'E ' be the event of odd numbers

Mae will roll an odd number

n(E) = {1, 3, 5} = 3

Step(ii):-

The probability that Mae will roll an odd number

$P(E) = \frac{n(E)}{n(S)} = \frac{3}{6}$

$P(E) = \frac{3}{6}$

4 0

3 years ago

Sofia wrote three numbers between 0.77 and 0.78 what numbers Sofia

Ostrovityanka [42]

Answer:

0.771, 0.772, 0.773

Step-by-step explanation:

three numbers between 0.77 and 0.78

0.77 = 0.770

and

0.78 = 0.780

So,

0.770, 0.771, 0.772, 0.773, 0.780

= 0.77, 0.771, 0.772, 0.773, 0.78

5 0

3 years ago

What is the slope of a line parallel to the line with equation 5x 3y=7?

adell [148]

-5/3
down 5, over 3
:)

6 0

3 years ago

A _[blank 1]_ is a number whose only factors are 1 and itself. If a number has other factors besides 1 and itself, it is called

kykrilka [37]

Numbers whose only factors are 1 and itself is known as prime numbers , numbers whose factors besides 1 and itself are composite numbers, we can use the sieve of Eratosthenes to determine whether the number is prime or composite.

Given a paragraph in which there are blanks:

A _____ is a number whose only factors are 1 and itself. If a number has factors besides 1 and itself, it is called a _____. You can use divisibility rules or _______ to help you determine whether a number is prime or composite.

We are required to fill the blank with appropriate options.

We have to fill "prime numbers" in the first blank.

We have to fill "composite numbers" in the second blank.

We have to fill "the sieve of Eratosthenes" in the third blank.

Hence numbers whose only factors are 1 and itself is known as prime numbers , numbers whose factors besides 1 and itself are composite numbers, we can use the sieve of Eratosthenes to determine whether the number is prime or composite.

Learn more about prime numbers at brainly.com/question/145452

#SPJ1

3 0

1 year ago

A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ

andreyandreev [35.5K]

The correct answer is C) t₁ = 375, $t_n=5t_{n-1}$ .

From the general form,
$t_n=75(5)^n$ , we must work backward to find t₁.

The general form is derived from the explicit form, which is
$t_n=t_1(r)^{n-1}$ . We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

$t_n=t_1(5)^{n-1}$

Using the products of exponents, we can "split up" the exponent:
$t_n=t_1(5)^n(5)^{-1}$

We know that 5⁻¹ = 1/5, so this gives us
$t_n=t_1(\frac{1}{5})(5)^n
\\
\\=\frac{t_1}{5}(5)^n$

Comparing this to our general form, we see that
$\frac{t_1}{5}=75$

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
$t_n=t_{n-1}(r)$ , while we must state what t₁ is; this gives us

$t_1=375; t_n=t_{n-1}(5)$

3 0

3 years ago