Answer:
I think the answer is B. I could be wrong tho, love.
Tyler is thinking of a number that must also be divisible by 6. I know that because any number that is divisible by both 2 and 3 is divisible by 6 as well.
Answer:
4
Step-by-step explanation:
There are 4 numbers to the right of decimals in question.
Pls mark Brainiest :)
Answer:
The real roots are
and 
The sum of the squares of these roots is 
Step-by-step explanation:
The given quadratic equation is
has two real roots.
To find the roots .

Dividing the above equation by 2


For quadratic equation
the solution is 
Where a and b are coefficents of
and x respectively, c is a constant.
For given quadratic equation
a=4, b=6, c=-7









The real roots are
and 
Now to find the sum of the squares of these roots
![\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B-3%2B%5Csqrt%7B37%7D%7D%7B4%7D%2B%5Cfrac%7B%28-3-%5Csqrt%7B37%7D%29%7D%7B4%7D%5Cright%5D%5E2%3D%5Cfrac%7B-3%2B%5Csqrt%7B37%7D-3-%5Csqrt%7B37%7D%7D%7B4%7D)


![\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B-3%2B%5Csqrt%7B37%7D%7D%7B4%7D%2B%5Cfrac%7B%28-3-%5Csqrt%7B37%7D%29%7D%7B4%7D%5Cright%5D%5E2%3D%5Cfrac%7B-3%7D%7B2%7D)
Therefore the sum of the squares of these roots is 
Answer:
7x-9
Step-by-step explanation: