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mezya [45]
4 years ago
14

Which graph is an example of a cubic function

Mathematics
2 answers:
Firlakuza [10]4 years ago
5 0
The graph of a cubic function has its ends in opposite direction.

A cubic function with positive coefficient rises towards right and falls towards left. 

A cubic function with negative coefficient rises towards left and falls towards right. 

The graph attached below shows the parent cubic function y = x³

liberstina [14]4 years ago
3 0

Answer:

B.

Step-by-step explanation:

on E 2020

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Which sequence of transformations maps triangle PQR onto its image triangle P'Q'R'
erica [24]

Answer:

Reflect, Translate, Dilate

Step-by-step explanation:

1. Reflect across the y-axis

2. Translate the triangle (x + 1, y + 1)

3. Dilate PQR by: \frac{3}{2}

8 0
3 years ago
A particle moves along the curve below. y = √ 8 + x 3 As it reaches the point ( 1 , 3 ) , the y -coordinate is increasing at a r
REY [17]

Answer:

<em>The x-coordinate is changing at 10 cm/s</em>

Step-by-step explanation:

<u>Rate of Change</u>

Suppose two variables x and y are related by a given function y=f(x). If they both change with respect to a third variable (time, for instance), the rate of change of them is computed as the derivative using the chain rule:

\displaystyle \frac{dy}{dt}=\frac{dy}{dx}\cdot \frac{dx}{dt}

We have

y=\sqrt{8+x^3}

Or, equivalently

y^2=8+x^3

We need to know the rate of change of x respect to t. We'll use implicit differentiation:

\displaystyle 2y\cdot \frac{dy}{dt}=3x^2\cdot \frac{dx}{dt}

Solving for dx/dt

\displaystyle \frac{dx}{dt}=\frac{2y\cdot \frac{dy}{dt}}{3x^2}

Plugging in the values x=1, y=3, dy/dt=5

\displaystyle \frac{dx}{dt}=\frac{2(3)\cdot 5}{3\cdot 1^2}=10

The x-coordinate is changing at 10 cm/s

7 0
3 years ago
HELP PLEASE now ASAP
frosja888 [35]
The line that is parallel is DE
6 0
3 years ago
7. What is the solution to x2 + 10x + 27 = 0 when written in the form a ± bi? (1 point)
son4ous [18]

Answer:

<u>The correct answer is D. -5 +/- i√2</u>

Step-by-step explanation:

Let's solve for x, the equation given to us, this way, using the quadratic formula:

x = (- b +/- √b² - 4ac)/2a

Replacing with the real values, we have:

x = (-10 +/- √10² - 4 * 1 * 27)/2

x = (-10 +/- √100 -108)/2

x = (-10 +/- √-8)/2

x = (-10 +/- √-1 * 4 * 2)/2 Let's recall that √-1 = i

x = (-10 +/- 2i√2)/2

x = 2 (-5 +/- i√2)/2 (Dividing by 2 both the numerator and the denominator)

<u>x₁ = -5 + i√2</u>

<u>x₂ = -5 - i√2</u>

<u>The correct answer is D. -5 +/- i√2</u>

7 0
4 years ago
Read 2 more answers
179÷10 to the first power
Elena-2011 [213]
17.9 hope this helped
6 0
3 years ago
Read 2 more answers
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