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harina [27]
2 years ago
5

Write the expression in complete factored form. p(b + 9) - (b + 9) =

Mathematics
1 answer:
kvasek [131]2 years ago
8 0

Answer:

(p-1)(b+9)

Step-by-step explanation: Both terms are a(b+9), but one term has a=p and the other is -1. So add them and get the answer

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the radius of a cone is 5cm and the height of a cone is 10 cm. what is the approximate volume of the cone? ASAP PLS
NeTakaya

Answer:

261.8

Step-by-step explanation:

8 0
3 years ago
Identify the coefficient of 17 ×y3 z12
Lemur [1.5K]
17 X y3z12 ? I would imagine 17 being the coefficient. I could be wrong because I don't quite understand the equation.
5 0
2 years ago
If p and q are non-zero rational numbers, and s and t are irrational numbers, select all of the statements that are always false
Svetllana [295]

Answer:

The false choices are A, C, and E

Step-by-step explanation:

Let's make an example:

p=1

q=2

s=sqrt(3)

t=sqrt(6)

Since pq=1*2=2, the answer is rational and A is false.

Since pt=1*sqrt(6)=sqrt(6), the answer is irrational and B is true.

Since p/q=1/2=0.5, the answer is rational and C is false.

Since st=sqrt(3)*sqrt(6)=sqrt(18), the answer is irrational and D is true.

Since s/t=sqrt(3)/sqrt(6)=sqrt(1/2), the answer is irrational and E is false.

4 0
3 years ago
F(x)=-10x-3 ; compressed horizontally by a factor of 5/8
notka56 [123]

Answer:

yes?

Step-by-step explanation:

7 0
2 years ago
What is the constant of variation for the quadratic variation? 0.1y = 3x2
svet-max [94.6K]

Answer:

The constant of variation for the given quadratic equation is, 30

Step-by-step explanation:

One of the form of a quadratic equation is written as:

y = kx^2     ....[1]

where k is the coefficient and for this case the constant of variation.

In order to obtain the answer for the given equation, we write the given equation to the form above.

0.1y=3x^2  or

y=(\frac{3}{0.1})x^2 or

y=30x^2

Comparing this equation with equation [1], to get the value of k;

k=30.

therefore, the  constant of variation is, 30.

6 0
3 years ago
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