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3 years ago

Which tab in Microsoft Word provides access to the backstage view?

Computers and Technology

2 answers:

ivann1987 [24]3 years ago

6 0

The answer is control windows

lbvjy [14]3 years ago

6 0

Solution:

The Backstage View in Word is the "behind the scenes" view of commands you can use to do file-related tasks, such as saving, opening, or printing a document. You access the Backstage View by selecting the FILE tab on the ribbon.

This the required answer.

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Write c++ program to find maximum number for three variables using statement ?

pantera1 [17]

Answer:

#include<iostream>

using namespace std;

int main(){

int n1, n2, n3;

cout<<"Enter any three numbers: ";

cin>>n1>>n2>>n3;

if(n1>=n2 && n1>=n3){

cout<<n1<<" is the maximum";}

else if(n2>=n1 && n2>=n3){

cout<<n2<<" is the maximum";}

else{

cout<<n3<<" is the maximum";}

return 0;

}

Explanation:

The program is written in C++ and to write this program, I assumed the three variables are integers. You can change from integer to double or float, if you wish.

This line declares n1, n2 and n3 as integers

int n1, n2, n3;

This line prompts user for three numbers

cout<<"Enter any three numbers: ";

This line gets user input for the three numbers

cin>>n1>>n2>>n3;

This if condition checks if n1 is the maximum and prints n1 as the maximum, if true

if(n1>=n2 && n1>=n3){

cout<<n1<<" is the maximum";}

This else if condition checks if n2 is the maximum and prints n2 as the maximum, if true

else if(n2>=n1 && n2>=n3){

cout<<n2<<" is the maximum";}

If the above conditions are false, then n3 is the maximum and this condition prints n3 as the maximum

else{

cout<<n3<<" is the maximum";}

return 0;

3 0

3 years ago

FREE 10 POINTS THE EASIEST QUESTION EVER I AM NEW SO I DONT KNOW HOW TO MARK SOMEONE THE BRAINLEAST ????????????????????????????

umka2103 [35]

Usually you can just report the question as useless or just report in in general. But I myself have read some answers and they dont even pertain to the question, it confuses me alot

8 0

3 years ago

Read 2 more answers

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0

2 years ago

During active listening, which response is NOT an example of providing feedback to the speaker to show that you understand his o

MaRussiya [10]

Answer:

The answer is D.

Explanation:

They/you are asking the speaker to clarify what they just said.

6 0

3 years ago

How do I get rid of this?

kherson [118]

There Is an App that you downloaded that allows this. you have to find it and disable it

3 0

3 years ago

Read 2 more answers