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faust18 [17]
3 years ago
8

Which tab in Microsoft Word provides access to the backstage view?

Computers and Technology
2 answers:
ivann1987 [24]3 years ago
6 0
The answer is control windows
lbvjy [14]3 years ago
6 0

Solution:

The Backstage View in Word is the "behind the scenes" view of commands you can use to do file-related tasks, such as saving, opening, or printing a document. You access the Backstage View by selecting the FILE tab on the ribbon.

This the required answer.

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What is the primary difference among a domain model, an analysis model, and a design model for the same project?
Aleks04 [339]

Answer:

The design model is the description of the model to be implemented, the analysis model is the model that links the design and the system or domain model while the domain model is the entire software implementation.

Explanation:

The domain model is the conceptual aspect of software engineering that comprises operational and data features. The analysis model is the schematic description of the system that links the design model to the system domain. The design model is also known as the object model as it shows an abstract representation of the implementation. It helps to test the quality of the software been developed.

8 0
3 years ago
Two friends can share 100 songs from their Bluetooth enabled mobile devices
Umnica [9.8K]

Answer:

A

Explanation:

If they are connected via bluetooth, you can share unlimited amounts of anything.

6 0
3 years ago
Vivian wants to increase the storage capacity of her computer. Which components should she upgrade?
Nikitich [7]

Answer:

Hard drive

Explanation:

The hard drive is where the operating system, programs and data reside on (unless the data is saved and backed up elsewhere). An older hard drive that uses platters for reading and writing data to it will be slower than a later model solid state device. Newer hard drives have very fast access speeds compared to older units.

4 0
3 years ago
A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co
tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k  ...(1)

probability of 2 hops = k(1-k)  ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

                                                       = (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

                                                       = k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops                = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

     ∞                             n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

    n-1

   = 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet =  k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet =  k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

6 0
3 years ago
Type (dog, cat, budgie, lizard, horse, etc.) Create a class that keeps track of the attributes above for pet records at the anim
Alenkinab [10]

Answer:

If you did the exercise with two Dog objects, it was a bit boring, right? After all, we have nothing to separate the dogs from each other and no way of knowing, without looking at the source code, which dog produced which bark.

In the previous article, I mentioned that when you create objects, you call a special method called a constructor. The constructor looks like the class name written as a method. For example, for a Dog class, the constructor would be called Dog().

The special thing about constructors is that they are the path to any new object, so they are a great place to call code that initializes an object with default values. Further, the return value from a constructor method is always an object of the class itself, which is why we can assign the return value of the constructor to a variable of the type of class we create.

However, so far, we have not actually created a constructor at all, so how come we can still call that method?

In many languages, C# included, the language gives you a free and empty constructor without you having to do anything. It is implied that you want a constructor; otherwise there would be no way of using the class for anything, so the languages just assume that you have written one.

This invisible and free constructor is called the default constructor, and, in our example, it will look like this:

public Dog(){ }

Notice that this syntax is very similar to the Speak() method we created earlier, except that we do not explicitly return a value nor do we even declare the return type of the method. As I mentioned earlier, a constructor always returns an instance of the class to which it belongs.

In this case, that is the class Dog, and that is why when we write Dog myDog = new Dog(), we can assign the new object to a variable named myDog which is of type Dog.

So let’s add the default constructor to our Dog class. You can either copy the line above or, in Visual Studio, you can use a shortcut: type ctor and hit Tab twice. It should generate the default constructor for you.

The default constructor doesn’t actually give us anything new because it is now explicitly doing what was done implicitly before. However, it is a method, so we can now add content inside the brackets that will execute whenever we call this constructor. And because the constructor runs as the very first thing in an object’s construction, it is a perfect place to add initialization code.

For example, we could set the Name property of our objects to something by adding code such as this:

public Dog()

{

   this.Name = "Snoopy";

}

This example will set the Name property of any new objects to “Snoopy”.

Of course, that’s not very useful because not all dogs are called “Snoopy”, so instead, let us change the method signature of the constructor so that it accepts a parameter.

The parentheses of methods aren’t just there to look pretty; they serve to contain parameters that we can use to pass values to a method. This function applies to all methods, not just constructors, but let’s do it for a constructor first.

Change the default constructor signature to this:

public Dog(string dogName)

This addition allows us to send a string parameter into the constructor, and that when we do, we can refer to that parameter by the name dogName.

Then, add the following line to the method block:

this.Name = dogName;

This line sets this object’s property Name to the parameter we sent into the constructor.

Note that when you change the constructor’s signature, you get a case of the red squigglies in your Program.cs file.When we add our own explicit constructors, C# and .NET will not implicitly create a default constructor for us. In our Program.cs file, we are still creating the Dog objects using the default parameter-less constructor, which now no longer exists.

To fix this problem, we need to add a parameter to our constructor call in Program.cs. We can, for example, update our object construction line as such:

Dog myDog = new Dog(“Snoopy”);

Doing so will remove the red squigglies and allow you to run the code again. If you leave or set your breakpoint after the last code line, you can look at the Locals panel and verify that your object’s Name property has indeed been? Got it?

5 0
2 years ago
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