All categories

3 years ago

-19+3x-11+2x=2 .......?

Mathematics

2 answers:

Tcecarenko [31]3 years ago

7 0

-19+3x-11+2x=2

-19-11+3x+2x= 2

-30+5x= 2

Move -30 to other side. Sign changes from -30 to +30 .

-30+30+5x= 2+30

5x= 32

Divide by 5

5x/5= 32/5

Cross out 5 and 5 , divide by 5. Becomes : x= 32/5

Rina8888 [55]3 years ago

4 0

Answer:

x=6.4

Step-by-step explanation:

-19+3x-11+2x=2

5x-30=2

5x=32

x=6.4

You might be interested in

What IS 23443x/3.14159

mamaluj [8]

Answer:

7462.14496x

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is the equivalent to 3/20 as a fraction

aalyn [17]

6/40 is equalvilant because all you have to do is double or simplify it by 2

5 0

2 years ago

Read 2 more answers

In which order should the four different digits be arranged to obtain the largest 4-digit number?

Rashid [163]

9999

Is ur answer mate......

4 0

2 years ago

Read 2 more answers

Someone please help! Thank you

borishaifa [10]

I think the answer would be D, but I’m not sure.

3 0

3 years ago

Read 2 more answers

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

2 years ago