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Whitepunk [10]
3 years ago
11

Suppose Neil Armstrong decided to throw a golf ball into the air while he was standing on the

Mathematics
1 answer:
lawyer [7]3 years ago
3 0

Answer:

At 7 seconds the instantaneous rate of change of the function s(t) with time which is the velocity is -11.18 m/s

Step-by-step explanation:

The given information on the height can be written as follows;

s(t) = -2.72·t² + 26.9·t + 6

Where;

s = The height (displacement) of the golf ball

t = The time taken during the motion of the golf ball

The velocity is found by finding the derivative of the displacement s as follows;

v = d(s(t))/dt = d(-2.72·t² + 26.9·t + 6)/dt = 2×(-2.72)×t + 26.9

When t = 7, v = 2×(-2.72)×7 + 26.9 = -11.18 m/s

Therefore the ball is coming down with 11.18 m/s speed at 7 seconds.

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erastovalidia [21]

Answer:

A. 6

Step-by-step explanation:

Using the Pythagorean theorem which states that: <u>Hypotenus² = Opposite² + Adjacent²</u>

Where: hypotenus = 10, opposite = x, adjacent = 8

So:

{10}^{2}  =  {x}^{2}  +  {8}^{2}

Solving for x

100 =  {x}^{2}  + 64

Collect like terms to make x the subject of formula

100 - 64 =  {x}^{2} →36 =  {x}^{2}

36 =  {x}^{2} ⟹ {x}^{2}  = 36

square root both sides of the equation to find the value of x

\sqrt{ {x}^{2} }  =  \sqrt{36} →x = 6

Therefore: Option A is correct

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1 year ago
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so if there are 4 events, then each one is 25% likely.

So the probability if them both occurring is 25%

I think
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