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Whitepunk [10]
3 years ago
11

Suppose Neil Armstrong decided to throw a golf ball into the air while he was standing on the

Mathematics
1 answer:
lawyer [7]3 years ago
3 0

Answer:

At 7 seconds the instantaneous rate of change of the function s(t) with time which is the velocity is -11.18 m/s

Step-by-step explanation:

The given information on the height can be written as follows;

s(t) = -2.72·t² + 26.9·t + 6

Where;

s = The height (displacement) of the golf ball

t = The time taken during the motion of the golf ball

The velocity is found by finding the derivative of the displacement s as follows;

v = d(s(t))/dt = d(-2.72·t² + 26.9·t + 6)/dt = 2×(-2.72)×t + 26.9

When t = 7, v = 2×(-2.72)×7 + 26.9 = -11.18 m/s

Therefore the ball is coming down with 11.18 m/s speed at 7 seconds.

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Answer:

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Its a perfect square and 27*3=81

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A parallelogram has base (2x - 1) metres and height (4x - 7) metres.
Jobisdone [24]

Answer:

0.4069 ; 1.843

Step-by-step explanation:

Given:

Base of parallelogram, b = (2x - 1)

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