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Tom [10]
3 years ago
8

(1, -6) and ( -8, 9 )

Mathematics
1 answer:
hichkok12 [17]3 years ago
6 0

Answer:

What is the question am I supposed to calculate the slope? If so then the answer is 5/-3

Step-by-step explanation:

 

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Simplify the expression. <br><br> 3√2 · √10
maw [93]

Answer:

Exact form = 6sqrt5

Step-by-step explanation:

7 0
3 years ago
Based on the tables, at what point do the lines y = 3x - 2 and y = -5x - 10 intersect?
Pepsi [2]
Intersect at where x=x and y=y
see where they have the same x and y values
that is at x=-1 and y=-5
intersect at (-1,-5)
8 0
3 years ago
Express the complex number 3(cos270° + i sin270°) in standard a + bi form.
Y_Kistochka [10]
Answer is choice C
The expression given is equivalent to -3i

============================================

Explanation:

Using a calculator, a reference sheet, or the unit circle, you'll find that:
cos(270) = 0
sin(270) = -1

So this means
z = 3(cos(270)+i*sin(270))
z = 3(0+i*(-1))
z = 3*0+3*i*(-1)
z = 0-3i
z = -3i
which is in a+bi form where a = 0 and b = -3
4 0
3 years ago
A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e
professor190 [17]

Answer:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

n=15 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =16 represent the sample variance

\sigma^2_0 =25 represent the value that we want to  verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 25

Alternative hypothesis: \sigma^2

The statistic is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And replacing we got:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0
3 years ago
Which letter of the alphabet is next in the series?<br> J O T Y D<br> (A) I (B) J (C) K (D) L
MaRussiya [10]

Answer:

A

i

Step-by-step explanation:

Hope it helps

4 0
3 years ago
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