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andrey2020 [161]

3 years ago

9

Please do this quick!

1 answer:

VMariaS [17]3 years ago

5 0

Answer:

(10 1/3,4)

Step-by-step explanation:

3x-5y=11

y=4

3x-5(4)=11

3x-20=11

3x=31

x= 10 1/3

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[tex]cos {}^{4} α+sin {}^{4} α= \frac{1}{4} (3+cos4α)<br>Prove:<br>

asambeis [7]

Given:

$\cos^4 \alpha+\sin^4\alpha=\dfrac{1}{4}(3+\cos 4 \alpha)$

To prove:

The given statement.

Proof:

We have,

$\cos^4 \alpha+\sin^4\alpha=\dfrac{1}{4}(3+\cos 4 \alpha)$

$LHS=\cos^4 \alpha+\sin^4\alpha$

$LHS=(\cos^2 \alpha)^2+(\sin^2 \alpha)^2$

$LHS=(\cos^2 \alpha+\sin^2\alpha)^2-2\sin ^2\alpha\cos^2 \alpha$ $[\because a^2+b^2=(a+b)^2-2ab]$

$LHS=(1)^2-2(1-\cos^2 \alpha)\cos^2 \alpha$ $[\because \cos^2 \alpha+\sin^2\alpha=1]$

$LHS=1-2\cos^2 \alpha+2\cos^4 \alpha$

Now,

$RHS=\dfrac{1}{4}(3+\cos 4 \alpha)$

$RHS=\dfrac{1}{4}[3+(2\cos^2 2\alpha-1)]$ $[\because \cos 2\theta=2\cos^2\theta -1]$

$RHS=\dfrac{1}{4}[2+2\cos^2 2\alpha]$

$RHS=\dfrac{1}{4}[2+2(2\cos^2 \alpha-1)^2]$ $[\because \cos 2\theta=2\cos^2\theta -1]$

$RHS=\dfrac{1}{4}[2+2(4\cos^4 \alpha-4\cos \alpha+1)]$ $[\because (a-b)^2=a^2-2ab+b^2]$

$RHS=\dfrac{1}{4}[2+8\cos^4 \alpha-8\cos \alpha+2]$

$RHS=\dfrac{1}{4}[4+8\cos^4 \alpha-8\cos \alpha]$

$RHS=1+2\cos^4 \alpha-2\cos \alpha$

$RHS=1-2\cos^2 \alpha+2\cos^4 \alpha$

$LHS=RHS$

Hence proved.

8 0

3 years ago

las edades de maría y susana suman 56 años si la edad de maría es los 3/5 de la edad de susana ¿ que edad tiene maría?

Murljashka [212]

Susana=s
maria=m

m= 3s/5

s+m=56
s+(3s/5)=56
(5s+3s)/5=56
8s=56*5
8s=280
s=280/8
s=35

35 --->5/5
x ---> 3/5

x= (3/5)*35 / (5/5)
x=21
edad de maria= 21 años

4 0

3 years ago

If the lowest paid players are on $1,000/week, how much do they earn per:

ololo11 [35]

Step-by-step explanation:

your answer is 84,000

4 0

3 years ago

Read 2 more answers

Which of the following is a measure of variation for a numerical data set ? Plz help

kipiarov [429]

I’m pretty sure it would be interquartile range, since range is the measure that measures variation within a data set.

5 0

3 years ago

Math question please help if you get this right I will mark you as a brainliest

san4es73 [151]

The Law of Cosines would be your best bet here, since the unknown side is opposite the known angle 110 degrees.

|AC|^2 = (8 in)^2 + (23 in)^2 - 2(8 in)(23 in)*cos 110 degrees

= 64 in^2 + 529 in^2 - (368 in^2)*(-0.342)

= 593 in^2 + 126 in ^2 approximately

= 719 in^2 approximately

Then the length of side AC is approx. √(716 in^2) = 27 in

3 0

3 years ago