Assumptions: Based on your question is seems like you are trying to find the distance the cue ball was initially at from the pocket from the minimum angle being 90 degrees.
Answer: In this case we can assume the minimum angle that the eight ball had after the collision was 90 degrees and therefore we can use Pythagoras Theorem (only can be used for right triangles). This gives us the length of both sides of that triangle we have constructed which are 8 in. and 6 in.. In the context of our drawing we want to find the hypotenuse of the triangle which would be the initial distance the eight ball was from the pocket (once again being at the most minimum possible angle). a^2=b^2+c^2 . a=sqrt(b^2+c^2) .
Plug in for b and c and you should get that it was greater than 10 in.
24 because
6x4=24
8x3=24
since that makes the two denominador alike than they are common (alike) and they are the denominators (duh)
-Dafne
Answer:
the correct answer is option C. 7/25
