Let 4 + 3x = u
then 3dx = du
or, <span>1/3∫<span>u√</span>du
</span>
= <span>1/3<span>u^<span>3/2</span></span>/(3/2)
</span>
= <span>2/9∗(4+3x<span>)^<span>3/2
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i need more info. Is this the whole question?
6x2(3x4)(x1 I’m pretty sure it’s right if not let me now and I’ll figure something out but..hope it helps u
Answer:
He practicably stole her money
Step-by-step explanation:
that scu m bag
<h3><u>
Answer:</u></h3>
33480783
<h2><u>
Step-by-step explanation:</u></h2>
<u>Finding the Common Ratio:</u>
We know that the formula for the common ratio of a GP is:
r = aₙ / (aₙ₋₁) <em>(Where n is any integer)</em>
<em>replacing the values, taking n=2</em>
r = -21 / 7
r = -3
<u>Solving for the 15th Term:</u>
We know that the Formula for the nth term of a GP:
G(n) = a * r ⁿ⁻¹ <em>(where a is the first term and r is the common ratio)</em>
<em>replacing the values (taking n = 15 since we need the 15th term)</em>
G(15) = 7 * (-3)¹⁴
G(15) = 33480783
Hence, the 15th term of the given GP is 33480783
