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3 years ago

9

Integral sqrt(4+3x) dx

1 answer:

Alisiya [41]3 years ago

3 0

Let 4 + 3x = u

then 3dx = du

or, <span>1/3∫<span>u√</span>du
</span>
= <span>1/3<span>u^<span>3/2</span></span>/(3/2)
</span>
= <span>2/9∗(4+3x<span>)^<span>3/2

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Natasha2012 [34]

Answer:

The exact solution is

$x = \frac{Ln(60)}{7*Ln(5)}$

And the approximation to three decimal places is:

x = 0.363

Step-by-step explanation:

Here we have the equation:

$5^{7*x} = 60\\$

Now we can remember a property of the natural logarithm function:

Ln(a^n) = n*Ln(a)

Now we can apply the Ln( ) function to both sides of that equation to get:

$Ln(5^{7*x}) = Ln(60)$

Then we get:

$7*x*Ln(5) = Ln(60)$

Solving that for x we get:

$x = \frac{Ln(60)}{7*Ln(5)} = 0.363$

So the exact solution is:

$x = \frac{Ln(60)}{7*Ln(5)}$

And the approximation to three decimal places is:

x = 0.363

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Nitella [24]

Answer:given below

Step-by-step explanation:

sqrt x^2 +81= x + 10

x^2 + 81 = (x+10)^2

x^2 + 81 = x^2 + 20x + 100

so answer is:

x^2 + 81 = x^2 +20x + 100

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mote1985 [20]

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