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Delicious77 [7]
3 years ago
9

A candy company makes boxes of chocolates. Each box has 32 chocolates total. Of those 32 chocolates 14 of them have nuts. If the

re were enough boxes for a total of 608 chocolates, how many of them would have nuts
Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0

Answer: 266

Step-by-step explanation: This is a ratio problem. If there are 14 chocolates with nuts out of every 32 chocolates, you can use this as a ratio and set it up as a proportion.

(1) 14 chocolates w/ nuts / 32 chocolates = n chocolates / 608 chocolates

(2) Solve for n: 8,512 = 32n; n = 266

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3 years ago
Which equation represents the statement: Three times the sum of a number and 5 is –30?
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Answer:

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In other words, 12 + 3 = 15.

That 3 that we are adding is our common difference.

So we know that our first term is 12.

Now we can continue the sequence.

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24 ⇒ <em>5th term</em>

27 ⇒ <em>6th term</em>

30 ⇒ <em>7th term</em>

33 ⇒ <em>8th term</em>

36 ⇒ <em>9th term</em>

39 ⇒ <em>10th term</em>

42 ⇒ <em>11th term</em>

45 ⇒ <em>12th term</em>

48 ⇒ <em>13th term</em>

51 ⇒ <em>14th term</em>

54 ⇒ <em>15th term</em>

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This means that the 20th term of this arithemtic sequence is 69.

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