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trasher [3.6K]
3 years ago
8

Y/a −b= y/b −a, if a≠b solve for y

Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Answer:

y= ab    if a≠b

Step-by-step explanation:

y/a −b= y/b −a

multiply each side by ab to clear the fractions

ab(y/a −b) = ab( y/b −a)

distribute

ab * y/a - ab*b = ab * y/b - ab *a

b*y - ab^2 = ay -a^2 b

subtract ay on each side

by -ay -ab^2 = ay-ay -a^2b

by -ay -ab^2 =-a^2b

add ab^2 to each side

by-ay -ab^2 +ab^2 = ab^2 - a^2b

by-ay = ab^2 - a^2b

factor out the y on the left, factor out an ab on the right

y (b-a) = ab(b-a)

divide by (b-a)

y (b-a) /(b-a)= ab(b-a)/(b-a)    b-a ≠0   or b≠a

y = ab

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Look at the image please helppp
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Step-by-step explanation:

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step 2

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7 0
3 years ago
The cost in dollars of making x items is given by the function C(x)=10x+900 .
Stella [2.4K]

For the given cost equation we have:

a) Fixed cost is $900.

b) For making 25 items the cost is $1150.

c) D: x ∈ [0, 150]

   R: c ∈ [900, 2400]

<h3>Working with the cost equation.</h3>

Here we know that the cost equation is:

c(x) = 10*x + 900.

First, we want to get the fixed cost, it is given by evaluating the function in x = 0.

c(0) = 10*0 + 900 = 900

The fixed cost is 900.

b) Now we want to get the cost for making 25 items, to get this, we just evaluate in x = 25.

c(25) = 10*25 + 900 = 250 + 900 = 1150

c) Now, if the maximum cost is 2400, then the maximum number of items that we can make is x₀, such that:

c( x₀) = 2400 = 10*x₀ + 900

Solving for x₀ we get:

x₀ = (2400 - 900)/10 = 150

Now we want to get the range and domain.

We know that we can make between 0 and 150 items, so the domain is:

D: x ∈ [0, 150]

For the range, we know that the fixed cost for 0 items is 900, and the maximum cost is 2400, then the range is:

R: c ∈ [900, 2400]

If you want to learn more about domain and range:

brainly.com/question/10197594

#SPJ1

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2 years ago
What's the equivalent expression ​
Mkey [24]

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The third and fourth ones are correct
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