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Minchanka [31]
3 years ago
8

PLZ HELP ME!!!!! NO LINKS!!!!!!!!!!

Mathematics
1 answer:
fomenos3 years ago
8 0

Answer:

unfortunately, I couldn't give you the answer because I can't see all of the number values provided in this problem, but hopefully with the explanation you'll be able to solve it : )

Step-by-step explanation:

1. To find the mean absolute deviation of the data, start by finding the mean of the data set.

2. Find the sum of the data values, and divide the sum by the number of data values.

3. Find the absolute value of the difference between each data value and the mean: |data value – mean|.

4. Find the sum of the absolute values of the differences.

5. Divide the sum of the absolute values of the differences by the number of data values.

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Simplify 18/5 to get the answer
Inga [223]
5\frac{3}{5}
4 0
3 years ago
Help please thank you
kozerog [31]
To solve this question, we can use the tangent. The adjacent leg to the angle will have a length of 9.3 and the opposite leg will have a length of 7.4

Using these, we can create an equation to solve for unknown angle (let it be x) using the tangent.

\tan(x)=\dfrac{7.4}{9.3}

Take the inverse tangent, or arc tangent, on both sides.

x=tan^{-1}(\dfrac{7.4}{9.3})
\approx 39

Your answer is the first choice. I hope this helps! :)
4 0
4 years ago
First verify that y(x)y(x) satisfies the given differential equation. Then determine a value of the constant CC so that y(x)y(x)
zubka84 [21]

Answer:

at constant C = -56 satisfies the given condition of y(x)

Step-by-step explanation:

differentiate y(x) w.r.t.x

y' (x ) = \frac{d}{dx} (\frac{1}{4} x^5 +Cx^{-3} )

        = \frac{1}{4}\frac{d}{dx} (x^5) + C\frac{d}{dx}  (x^{-3} )

        = \frac{5}{4} x^4 - 3Cx^{-4}

attached is the remaining part of the detailed solution and the sketch of the several typical solutions

6 0
3 years ago
I NEED HELP ASAP!!!!
stiv31 [10]

Answer:

c

Step-by-step explanation:

or b because you are dividing I think 90 to 50 and 12

4 0
3 years ago
Drag the values to order them from least to greatest, with the least at the top.
GuDViN [60]

\bf 4\pi \qquad \approx \qquad 12.57 \\\\[-0.35em] ~\dotfill\\\\ \sqrt{79}+\sqrt{63}\qquad \approx \qquad 8.89 + 7.94\implies 16.83 \\\\[-0.35em] ~\dotfill\\\\ \sqrt{143}\qquad \approx \qquad 11.96 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{11.96}{\sqrt{143}}\qquad \stackrel{12.57}{4\pi }\qquad \stackrel{16.83}{\sqrt{79}+\sqrt{63}}~\hfill

6 0
3 years ago
Read 2 more answers
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