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Minchanka [31]
3 years ago
8

PLZ HELP ME!!!!! NO LINKS!!!!!!!!!!

Mathematics
1 answer:
fomenos3 years ago
8 0

Answer:

unfortunately, I couldn't give you the answer because I can't see all of the number values provided in this problem, but hopefully with the explanation you'll be able to solve it : )

Step-by-step explanation:

1. To find the mean absolute deviation of the data, start by finding the mean of the data set.

2. Find the sum of the data values, and divide the sum by the number of data values.

3. Find the absolute value of the difference between each data value and the mean: |data value – mean|.

4. Find the sum of the absolute values of the differences.

5. Divide the sum of the absolute values of the differences by the number of data values.

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Determine whether the improper integral converges or diverges, and find the value of each that converges.
sineoko [7]

Answer:

Since the \lim_{x\to -\infty} \frac{1}{(x-2)^2}=0 then we have this:

\int_{-\infty}^{-1} (x-2)^{-3} dx =-\frac{1}{18}

And we see that our integral on this case converged to -1/18.

Step-by-step explanation:

For this case we need to determine if the following integral converges or not:

\int_{-\infty}^{-1} (x-2)^{-3} dx

We can rewrite the integral like this:

\int_{-\infty}^{-1} \frac{1}{(x-2)^3} dx

Then we can use the substitution u = x-2 and then du = dx and we have this:

\int_{-\infty}^{-3} \frac{1}{u^3} du=\int_{-\infty}^{-3} u^{-3} du

If we solve the integral we got:

=\frac{u^{-3+1}}{-3+1} =-\frac{u^{-2}}{2}=-\frac{1}{2}\frac{1}{u^2}

And then the integral would be equal to:

\int_{-\infty}^{-1} (x-2)^{-3} dx = -\frac{1}{2(x-2)^2}\Big|_{-\infty}^{-1}

And if we replace and using the fundamental theorem of calculus we got:

= -\frac{1}{2} [\frac{1}{(-1-2)^2} -\lim_{x\to -\infty} \frac{1}{(x-2)^2}]

Since the \lim_{x\to -\infty} \frac{1}{(x-2)^2}=0 then we have this:

\int_{-\infty}^{-1} (x-2)^{-3} dx =-\frac{1}{18}

And we see that our integral on this case converged to -1/18.

5 0
3 years ago
Part A
natulia [17]

Answer:

To find the measure of an interior angle of a regular polygon, take the sum of all interior angles and divide by the number of angles. The sum of all interior angles can be found by (n - 2)*180 where n is the number of sides, in this case 24. So all the interior angles add to 3960 degrees.

PLEASE SAID THANKS

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Two Integers, a and b, have different signs. The absolute value of integer a is divisible by the absolute
klemol [59]

Answer:

ssorry i am 2ncd grade

Step-by-step explanation:

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Answer: Angles A and C are vertical angles.

Step-by-step explanation:

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I need answers quick!!!
Rudik [331]

Answer:

60

Step-by-step explanation:

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