Answer:
So the answer is in your thoughts and also in your mind so therefor the answer is the fisherman is more farther away just by looking at him
Step-by-step explanation:
Answer:
∠KNC = 99°
Step-by-step explanation:
∠JNM + ∠KNC = 180 (it is a straight line)
∠KNC = 180 - ∠JNM
∠KNC = 180 - 81
∠KNC = 99°
For the first drawing, there are 30 tickets altogether, and Jason
has 10 of them. The probability that one of his tickets will win is
10 / 30 .
For the second drawing, there are 29 tickets altogether, and Jason
has 9 of them. The probability that one of his tickets will win is
9 / 29 .
For the third drawing, there are 28 tickets altogether, and Jason
has 8 of them. The probability that one of his tickets will win is
8 / 28 .
The probability that all three of these things will happen is
(10/30) x (9/29) x (8/28) = 720 / 24,360
= 6 / 203 = 2.96 percent (rounded)
35. an open circle means there is no equal sign, and shading to the left means less then...so inequality is : x < 6
36. a closed circle means there is an equal sign, and shading to the left means less then.... x < = 9
in short...a closed circle means there is an equal sign, an open circle means there is not. if it is shaded to the left, it is less then...if it is shaded to the right, it means it is greater then.
37. x > 4
38. x > = 4
39. x < 1
40. x < = 5
41. x > = 5
42. x < 0
I will give two solutions, one where everything is cubed and one where just the 3 is cubed, because I don't know what you meant.
Just the 3 is cubed solution(Which I think is correct because it has a nicer answer):
Answer:

Step-by-step explanation:
We have that
.
We can subtract
from both sides of the equation to get
.
We can then divide by
to get
.
So,
and we're done!
Everything is cubed solution:
Answer:
![\sqrt[3]{5}-3/2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%7D-3%2F2)
Step-by-step explanation:
We have that
.
We can take the cube root of both sides to get
.
Note that
, so
.
So, we want to solve
.
We can subtract
from both sides to get
.
We can then divide both sides by
to get
.
So,
and we're done!