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e-lub [12.9K]
3 years ago
15

Answer question and show work please

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
5 0
The recipes include: \frac{1}{2}\frac{3}{8}\frac{3}{10}
finding their lcm gives:
\frac{12,20,15}{40}
arranging them 
\frac{3}{10}\frac{3}{8}\frac{1}{2}
please mark as brainliest
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8 0
3 years ago
Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.2 centimeters (
MAVERICK [17]

Answer:

The interval [32.6 cm, 45.8 cm]

Step-by-step explanation:

According with the <em>68–95–99.7 rule for the Normal distribution:</em>  If \large \bar x  is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval

\large [\bar x - s, \bar x +s]

around 95% of the data must fall in the interval

\large [\bar x -2s, \bar x +2s] 

around 99.7% of the data must fall in the interval

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So, the range of lengths that covers almost all the data (99.7%) is the interval

[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]

<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>

3 0
3 years ago
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