The median is 44 (the center line)
Answer:
It's a bit unclear with the table this way, but I count fifteen points, fifteen lines of the table, each a pair of numbers.
That's 15 degrees of freedom in the data. When modeling, each parameter in the model uses up one degree of freedom, so you'd use a smaller number of degrees of freedom when calculating t statistics, etc.
This is relatively easy because that 25 is a perfect square, whose (square) roots are 5 and -5. x^2-10x+25 = (x - 5)(x - 5). Note how (-5)(-5) = +25, and how -5x - 5x = -10x.
The roots are { (x-5), (x-5) }.
Start by finding the slope of the line by doing m(slope)=y2-y1 over x2-x1 using the pairs and then plug in the y and x of one of the points into the equation y=mx+b (y in the y and x in the x spot) and solve for b. Then plug the slope (can be a fraction shouldn’t be decimal) and y-intercept (b) back in the equation of a line above and you have your answer!
