Answer:
- 3, - 1, 1
Step-by-step explanation:
To find the first 3 terms substitute n = 1, 2, 3 into the formula
a₁ = 2(1) - 5 = 2 - 5 = - 3
a₂ = 2(2) - 5 = 4 - 5 = - 1
a₃ = 2(3) - 5 = 6 - 5 = 1
The first 3 terms are - 3, - 1, 1
We have that
the expression 2f + 4f + 2 – 3-------> we can group it (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]
if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17
<span>let's check it
</span>[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok
6 times because 6•7=42 so it must be 6 because 7•7=49
Good luck!!
Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)
You should already know this:

You should also know this:

So plugging in both of those into our identity, we get:

Simplify the denominator on the LHS (Left Hand Side)
We get:

LHS = RHS
Therefore, identity is verified.
I think it's 3 but idk I'm not good at math