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neonofarm [45]
3 years ago
6

Common factors of 28 and 40

Mathematics
1 answer:
Nady [450]3 years ago
7 0
28: 1, 2, 4, 7, 14, 28

40: 1, 2, 4, 5, 8, 10, 20, 40

The common factors are 1, 2, and 4.

You can use a factor rainbow to help you find the factors (:
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Find the value of k such that lim-->4 (x^2+x-k)/(x-4) exists
7nadin3 [17]

Answer:

k=20

Step-by-step explanation:

when x approaches 4, the denominator x-4 approaches 0

if the denominator is 0, it means that this is invalid

if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit

so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4

so x^2 + x - k = 0 when x = 4

4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20

6 0
3 years ago
Half the marbles in a bag are red, 1/6 of the marbles are blue, and the remaining 8 marbles are white how many total marbles are
Gemiola [76]

Hey there! I'm happy to help!

Let's represent the total number of marbles with the variable t. We have the following information.

1/2t+1/6t+8=t (1/2 of total are red, 1/6 of total are blue, 8 are white, add them up to get total)

Now, we solve for t.

1/2t+1/6t+8=t

We combine like terms.

2/3t+8=t

We subtract t from both sides.

-1/3t+8=0

We subtract 8 from both sides.

-1/3t=-8

We divide both sides by -1/3.

t=24

Therefore, there ae 24 total marbles in the bag.

Have a wonderful day! :D

7 0
3 years ago
Nuala drives to her grandma's.
weqwewe [10]

Answer:

25 minutes

If she's going double the speed, it'll take half the time.

4 0
3 years ago
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-5(c-4)=<br> a*-20-5c<br> b*20-5c<br> c*20+5c<br> ???????
Masteriza [31]

Answer:

b

Step-by-step explanation:

distributive property-

-5c-(-20) which is -5c+20 which can also be 20-5c

7 0
2 years ago
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What is the intersection of the three sets: A = {0, 2, 3, 6, 8}, B = {2, 3, 6, 8, 9}, and C = {1, 2, 4, 8, 9}? A. {2, 8, 9} B. {
Ugo [173]

Answer:

{2,8}

Step-by-step explanation:

This is the same thing as asking what element (in this case what number) is in all 3 sets.

0 isn't in all 3 sets because it isn't in B.

2 is in all 3 sets

3 isn't because it isn't in C

4 isn't in A.

6 isn't in C.

8 is in all 3 sets.

9 isn't in A

So the elements that are in the 3 sets are {2,8}.

8 0
3 years ago
Read 2 more answers
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