We are given with two equations to find the values of two variables, hence the problem can be solved.
Adding the two equations:
x + y = 12<u>x - y = 10
</u>2x = 22
<u />x =11
y = 1
No, it is not a perfect cube. A perfect cube is a number that is obtained when you cube an integer. For example, 8 (cube of 2), 27 (cube of 3) and 64 (cube of 4). Since -3 cannot be obtained by cubing an integer, it is not a perfect cube.
<span> He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x2, –x, –6x, and 6.</span>
From the box plot, it can be seen that for grade 7 students,
The least value is 72 and the highest value is 91. The lower and the upper quartiles are 78 and 88 respectively while the median is 84.
Thus, interquatile range of <span>the resting pulse rate of grade 7 students is upper quatile - lower quartle = 88 - 78 = 10
</span>Similarly, from the box plot, it can be seen that for grade 8 students,
The
least value is 76 and the highest value is 97. The lower and the upper
quartiles are 85 and 94 respectively while the median is 89.
Thus, interquatile range of the resting pulse rate of grade 8 students is upper quatile - lower quartle = 94 - 85 = 9
The difference of the medians <span>of the resting pulse rate of grade 7 students and grade 8 students is 89 - 84 = 5
Therefore, t</span><span>he difference of the medians is about half of the interquartile range of either data set.</span>
