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Orlov [11]
3 years ago
13

Isabel joins a service to download movies. She pays $2 per movie, but she gets the first 5 movies for free. How many movies, m,

can she download for $50?
Three of these equations give the correct value of m. Which equation does NOT?
Mathematics
2 answers:
Damm [24]3 years ago
3 0

The first question the answer to it is 30.

To do that divide 50/2 and see how many movies she can buy, which 25, then add the 5 free movies which gives you 30.

And the second part of the question I think is missing a picture or something.

balu736 [363]3 years ago
3 0

Answer:

2(m+5)=50

Step-by-step explanation:

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amid [387]

Answer:

Put your equation into this!

Step-by-step explanation:

desmos.com/calculator

It will graph it for you!

You are very welcome!!

3 0
4 years ago
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A rectangular table is 5 1/4 feet by 3 3/4 feet. What is the area of the table?
enot [183]

Answer:

19 11/16 or 315/16

Steps:

Turn the fractions into an improper fraction and then multiply straight across

5 1/4 = 21/4

3 3/4 = 15/4

(21/4)*(15/4)= 315/16= 19 11/16

Yes you got it right :)

4 0
3 years ago
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Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
3 years ago
In two or more complete sentences explain how you would set up and solve the following equation: Peter opened his account with $
Lilit [14]
What you would do is you would keep subtracting (I recommend a calculator for this task) from both accounts until you get an equal amount for each. You would also have to record this down that way you know each time what you got. (And please do not put the calculator part). Really hope this helps!!!

4 0
3 years ago
A number cube with faces labeled from 1 to 6 was rolled 20 times. Each time the number
aliina [53]
3+5=8
8/20 =.4
.4 goes to 40% bc you move the decimal over twice
3 0
3 years ago
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